Question 226083 in Javascript Question posted in
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How to get button to change visibility based on checkbox in JavaScript

new to JS here and working on a react project, I want to essentially have the button’s visibility attribute which is set to false to change to true when a checkbox is checked, here is my code and I believe the logic is there but for some reason is not reflected on the UI, any advice is appreciated

    const [visible, setVisibility] = useState(false)

    function clicked() {
        console.log('in cliked')
        const check = document.getElementById('acknowledged')
        check.addEventListener('click', showContinueButton())
        setVisibility(true)
    }


    function showContinueButton() {
        
        const continueButton = document.getElementById('continue')

        console.log(continueButton.getAttribute("visibility"))
        if(visible) {
            console.log('in the visible for loop')
            continueButton.setAttribute('visibility', 'visible')
        }
        
    }

the code above is the code I have defined before the return JSX, then within the JSX I call this code as followed…

<input type='checkbox' id='acknowledged' onClick={clicked}></input>

So essentially when this checkbox is clicked, using the onClick attribute, I pass the click function I passed earlier which has an eventListener with a callback function to change the visibility of the button

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2

Answers


  1. 0

    I want to point out that there are a lot of classical JavaScript logic in your functions, which should be used via hooks, and not directly.

    Hence these vanilla functions have better alternatives in React.

    document.getElementById();
getAttribute();
setAttribute();

    The right way to resolve your issue should instead be as follows:

    import { useState } from "react";

export default function App() {
  // 1. the variable 'visible' has initial value equal to false
  const [visible, setVisible] = useState(false);

  /*
  3. The click handle button updates the state (variable value of visible) to opposite of whatever it is,
  if true , then false, if false, then true
   */
  function onClickHandle() {
    setVisible((visible) => !visible);
  }
  /*
  5. LOGIC
  This function is returned everytime the state of the application changes, meaning everytime a user clicks on the checkbox, the state of var visible changes, and hence the component rerenders.
  */
  return (
    <div className="App">
      <label>
        Checkbox
        {/* 2. The input checkbox has a onClick Handler function passed as reference, meaning that function will be called when the checkbox is clicked. */}
        <input type="checkbox" onClick={onClickHandle} />
      </label>
      {/* 4. Application - An example of how to handle the logic, I have used terinary operator but basically it is saying if the value of visible if visible, return 'checked', else return 'not checked' */}
      <h2>Check box is {visible ? "checked" : "not checked"}</h2>
    </div>
  );
}

    Working example here

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  2. 0

    With the use of a state, you don’t need to manipulate the CSS.

    Here is an example for your reference:

    const [visible, setVisibility] = useState(false);
let clicked = e => {
  setVisibility(e.target.checked);
}
return ( 
  <div>
     &nbsp; <input type = "checkbox" onClick = {clicked}/> 
     {
      visible &&
      <button> Button1 </button>
     } 
  </div>
)
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