Question 52770 in Javascript Question posted in
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How to write a regex which splits the string into an array when https and a trailing space are found in javascript

I’m working with strings. The string often contains something like this:

"The site https://example.com contains all the information you need"

So far I have this regex, which splits the string when https? is found

const rgx_link = /(?=https?://)/gi;

So in this case it would split the string into:

arr = ["The site ", "https://example.com contains all the information you need"];

I would like to modify the regex, so it also splits the string if a space is found after the url.

The desired result would look like this:

arr = ["The site ", "https://example.com", " contains all the information you need"];

The new regex "should look" something like this ((?=https?://)(s)), but it doesn’t work.

Any help would be greatly appreciated. Thank you.

const text = "The site https://example.com contains all the information you need";
const rgx_link = /(?=https?://)/gi;
const result = text.split(rgx_link);
console.log(result)

Edit 1: Wiktors suggestion is correct. Didn’t notice that the leading part of the regex was changed, so it didn’t work.

const text = "The site https://example.com contains all the information you need";
const rgx_link = /(https?://S*)/gi;
const result = text.split(rgx_link);
console.log(result)
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3

Answers


  1. 0 
    const text =
    "The site https://example.com contains all the information you need";
const rgx_link = /(?=https?://)/gi;
const result = text.split(rgx_link);

const url = result[1].split(" ")[0];
const rest = result[1].split(url + " ")[1];

const res = [result[0], url, rest];

console.log(res);

    Is this what you need?

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  2. 0

    You can use

    text.split(/(https?://S*)/i)

    Note that String#split method outputs all captured substrings when the regex contains capturing groups, so this regex, being entirely wrapped with a capturing group, basically tokenizes the string into URLs and non-URL tokens.

    Note the absence of the g flag, since String#split behavior by default is to split on all occurrences of the regex pattern.

    Pattern details

    • http – a http string
    • s? – an optional s char
    • :// – a :// substring
    • S* – zero or more non-whitespace chars.
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  3. 0

    in python I can search for an url then use the span position and use the end value to split the string after the url

    data="""The site https://example.com contains all the information you need"""

def find_url(text):
    return re.search(r'https?://[^s]*', text)

position=int(find_url(data).span()[1])

print(position)

print(data[0:position],data[position:-1])
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