Question 50006 in Javascript Question posted in
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I want to replace the first six digits of an account number to be ###### and the last three to be ### using regex – Javascript

let regex = /(^d{6})|(d{3}$)/gm;
n = n.toString();
n = n.replace(regex,'#');
return '#####' + n + "##"

This is my regex but it returns #5225# not the expected result which is ######5225###.

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2

Answers


  1. 0

    just you string slice, remove the first 6 and last 3 and return the result with additional # before and after

    function replaceChar( char ) {
    return '######' + char.toString().slice(6,-3) + '###'
}
console.log(replaceChar(9999991111333))
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  2. 0

    Use a replacer function and use repeat with the length of the match.

    const regex = /(^d{6})|(d{3}$)/gm;
let n = 111111234555;
n = n.toString();
n = n.replace(regex, x => '#'.repeat(x.length));
console.log(n);

    or using substring

    let n = 111111234555;
const result = '######' + n.toString().substring(6,9) + '###';
console.log(result);
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