Question 220264 in Javascript Question posted in
A very good W3school tutorial can be found here.

If else statement in JavaScript keeps returning last else statement no matter user input

     var age = prompt('How old are you?');
        if ('age' <= 5){
            alert("You are a baby!");
        }
        else if ('age' >= 5 && 'age' < 18){
            alert("You are a child!");
        }
        else if ('age' >= 18 && 'age' < 70){
            alert("You are an adult!");
        }
        else
            alert("You are a senior!");

So I am trying to make it change depending on user input for age. However, no matter the age I enter "You are a senior!" is the only alert that goes off.

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2

Answers


  1. 0

    You need to remove those inverted commas ‘ ‘ or quotes around age within If condition. By putting 'age', you are using it as a string, but it is a variable age.

      var age = prompt('How old are you?');
    if (age <= 5){
        alert("You are a baby!");
    }
    else if (age >= 5 && age < 18){
        alert("You are a child!");
    }
    else if (age >= 18 && age < 70){
        alert("You are an adult!");
    }
    else
        alert("You are a senior!");
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  2. 0

    the problem is that when you make the comparison if ('age' <= 5) because of the quotes surrounding age is saying "if the string age is less than the number five" and that won’t ever be true. Age is a variable that contains a number so as with all variables it shouldn’t be surrounded by quotation marks.

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