Question 184449 in Javascript Question posted in
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Javascript – Add values from Array to every Object in Array

For a project i need to push the values of an array into every object in another array.
What i have so far:

closed_status = [{
    "project_no": 5,
    "priority": 3,
    "s_status": "S8",
    "project_Status: closed"
  },
  {
    "project_no": 8,
    "priority": 1,
    "s_status": "S5",
    "project_Status: closed"
  },
  {
    "project_no": 12,
    "priority": 2,
    "s_status": "S2",
    "project_Status: closed"
  }
]
str = [
  "Value 1",
  "Value 2",
  "Value 3",
]
let result = []
closed_status.forEach((obj) => {
  str.forEach((newValue) => {
    result.push({ ...obj,
      newValue
    })
  })
})

…and this is the result i get

result = [{
"project_no" : 5,
"priority" : 3,
"s_status": "S8",
"project_Status: closed",
"newValue": "Value 1"
},
{
"project_no" : 5,
"priority" : 3,
"s_status": "S8",
"project_Status: closed",
"newValue": "Value 2"
},
{
"project_no" : 5,
"priority" : 3,
"s_status": "S8",
"project_Status: closed",
"newValue": "Value 3"
},
{
"project_no" : 8,
"priority" : 1,
"s_status": "S5",
"project_Status: closed",
"newValue": "Value 1",
},
{
"project_no" : 8,
"priority" : 1,
"s_status": "S5",
"project_Status: closed",
"newValue": "Value 2",
}]

…and so on…
But what i am trying to get is:

{
"project_no" : 5,
"priority" : 3,
"s_status": "S8",
"project_Status: closed",
"newValue": "Value 1",
},
{
"project_no" : 8,
"priority" : 1,
"s_status": "S5",
"project_Status: closed",
"newValue": "Value 2",
},
{
"project_no" : 12,
"priority" : 2,
"s_status": "S2",
"project_Status: closed",
"newValue": "Value 3",
},

Anyone knows where my mistake is?

Thanks in advance

Tags:

4

Answers


  1. 0

    Assuming, that closed_status and str always have the same length, which it looks like from your example and wanted result, then you could do the following.

    for (let i = 0; i < closed_status.length; i++) {
    closed_status[i].newValue = str[i]
}
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  2. 0

    I guess you want to fill the array of objects with the values of str.

    You could do this by keeping track of the index:

    closed_status = [{
    "project_no": 5,
    "priority": 3,
    "s_status": "S8",
    "project_Status": "closed"
  },
  {
    "project_no": 8,
    "priority": 1,
    "s_status": "S5",
    "project_Status": 'closed'
  },
  {
    "project_no": 12,
    "priority": 2,
    "s_status": "S2",
    "project_Status": "closed"
  }
]
str = [
  "Value 1",
  "Value 2",
  "Value 3",
]

closed_status.forEach((obj,index) => {
  obj.newValue = str[index]
})

console.log(closed_status)
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  3. 0

    If you’re sure str and closed_status have the same amount of items, you could use str.shift() to shift out a single value that you spread into the original object.

    closed_status = [
  {
    "project_no": 5,
    "priority": 3,
    "s_status": "S8",
    "project_Status": "closed"
  },
  {
    "project_no": 8,
    "priority": 1,
    "s_status": "S5",
    "project_Status": "closed"
  },
  {
    "project_no": 12,
    "priority": 2,
    "s_status": "S2",
    "project_Status": "closed"
  }
]
str = [
  "Value 1",
  "Value 2",
  "Value 3",
]

closed_status = closed_status.map(e => ({ ...e, newValue: str.shift() }) );
console.log(closed_status);
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  4. 0

    The following solution assumes the first array is longer than the second. However, the lengths are always the same then i < str.length ? i : i % str.length can be replaced by i.

    const
closed_status = [{
    "project_no": 5,
    "priority": 3,
    "s_status": "S8",
    "project_Status": "closed"
  },
  {
    "project_no": 8,
    "priority": 1,
    "s_status": "S5",
    "project_Status": "closed"
  },
  {
    "project_no": 12,
    "priority": 2,
    "s_status": "S2",
    "project_Status": "closed"
  }
],
str = [
  "Value 1",
  "Value 2",
  "Value 3",
],
result = closed_status
.map((status,i) => ({...status, newValue:str[i < str.length ? i : i % str.length]}));

console.log( result );

//alternatively, (EQUAL LENGTHS)
console.log( str.map((newValue,i) => ({...closed_status[i],newValue})) );
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