Question 173862 in Javascript Question posted in
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Javascript – Alternative code for filling an array with a series incremented by any value

The following typescript function seriesIncrementedBy5 returns an array with numbers starting from 5 to upperLimit with an increment of 5.

Is there a way to replace this 5 lines of code with any recent typescript ES6 advanced function which will take less than 5 lines.

private seriesIncrementedBy5(upperLimit: number): number[] {
    const series = [];
    for (let s = 5; s <= upperLimit + 5; s += 5) {
        series.push(s);
    }
    return series;
}
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3

Answers


  1. 0

    You can create an array of the correct size and then map over it.

    const seriesIncrementedBy5 = upperLimit => [...Array((upperLimit/5|0)+1)]
        .map((_, i) => 5 * (i + 1));
console.log(seriesIncrementedBy5(10));
console.log(seriesIncrementedBy5(9));
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  2. 0

    You can use the Array.from method.

    private seriesIncrementedBy5(upperLimit: number): number[] {
  return Array.from({ length: Math.floor(upperLimit / 5) }, (_, i) => (i + 1) * 5);
}

    https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from

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  3. 0

    You can use Array.from, which can accept an object with the length: number property and a second argument populating function:

    const seriesIncrementedBy5 = (upperLimit: number): number[] =>
  Array.from({ length: Math.floor(upperLimit / 5) + 1 }, (_, i) => (i + 1) * 5);

    To calculate the length, we divide the upperLimit by 5 and floor it to get an integer; it is crucial to add + 1 to include the upperLimit in the array. To populate, we will use the element’s index; since we are starting from 5, not 0, we will add + 1 to the index and multiply it by 5.

    playground

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