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Javascript – Can a function be declared as pure at definition?

According to Webpack documentation:

It can be put in front of function calls to mark them as side-effect-free. Arguments passed to the function are not being marked by the annotation and may need to be marked individually.

Can we write PURE function at declaration ? Something like:

var max = /*#__PURE__*/(a,b) => { return (a>b)?a:b }

If yes, what is the right syntax?

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2

Answers


  1. 0

    As far as I know, there is no way you can declare function as pure in JavaScript.

    TypeScript has a proposal to introduce pure keyword for functions and methods, but currently this is just a draft proposal. You can read the whole thread, if you want here. The thread contains a comment with draft proposal description. When and whether at all this idea will be implemented is very hard to say.

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  2. 0

    Like Bogdan Gishka noted, there is no (formal) way to declare a function as pure. Maybe it’s an idea to use a Symbol for it?

    const pure = Symbol('pure');
const max = (a,b) => a > b ? a : b;
max[pure] = true;

console.log(`max(21,1): ${max(21, 1)}; max[pure]: ${max[pure]}`);
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