Question 305959 in Javascript Question posted in
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Javascript – create two-dimensional array

I’m new. I have an array

[1, 0, 0, 0, 0, 2, 4, 0, 0, 0, 0, 0, 0, 0, 5, 6]

I want to get a two-dimensional array from it

[[0, 0, 0,0],
[0, 0, 0, 0, 0, 0, 0,]]

how to do this without regular expressions

I have a solution where I use regular expressions with the split method, but need a variant without regular expressions and so that you get an array of zeros, not a string of zeros

    function zeroGroups(arr){
        const allZerosGroups = arr
          .map(item => item !== 0 ? '-' : 0)
          .join('')
          .split(/[^0]/)
          .filter(item => item.length !== 0)
          
        return allZerosGroups
    }
console.log(zeroGroups([1, 0, 0, 0, 0, 2, 4, 0, 0, 0, 0, 0, 0, 0, 5, 6])) // [ '0000', '0000000' ]
Tags:

2

Answers


  1. 0

    Loop through and check along the way. This is one way to do it:

    var arr =  [1, 0, 0, 0, 0, 2, 4, 0, 0, 0, 0, 0, 0, 0, 5, 6]
    var container = []
    containerCount = 0
    arrCount = 0
    var dArr = []
    arrLen = arr.length
    loop1:
    for (i = 0;i< arrLen;i++) {
        if (arr[i] == 0) {                                                              
            dArr[arrCount] = arr[i]  
            arrCount++    
            console.log(dArr)                 
        } else if (arrCount == 0) {
            continue
        } else {
            container[containerCount] = dArr                        
            arrCount = 0
            containerCount++    
            dArr = []                
        }                
    }

    console.log(container)
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  2. 0

    Hope, this helps.

    let arr1 = [1, 0, 0, 0, 0, 2, 4, 0, 0, 0, 0, 0, 0, 0, 5, 6];

let res = [];
let temp = []; 

arr1.map((item)=>{
  if(item === 0){temp.push(item)}
  else {
    if (temp.length!=0){
      res.push(temp); 
      temp = [];
    }
  }
 });

console.log(res);
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