Question 214987 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – Determine if object property includes array value

Given the following array

[60, 1456]

How can I determine which items in this object do not have a corresponding id to the numbers in the array?

[
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
]
Tags:

2

Answers


  1. 0 
    You can try combination of filter & includes or filter & find or filter indexOf

const a = [60, 1456];

const b = [
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
];

const idExists = b.filter(ob => {
 // const includes = !a.includes(ob.id);
 const find = a.find(id => id !== ob.id);

  return find;
})

    // Efficient approach

    const mapOfIds = a.reduce(acc, id => {...acc, [id]: id}, {});
const idExists = b.filter(ob => !mapOfIds[ob.id]);
    Login or Signup to reply.
  2. 0

    Use filter() combined with includes() to check if the id does not (!) exists in the ids array:

    const ids = [60, 1456];
const data = [
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
];

const res = data.filter(({ id }) => !ids.includes(id));
console.log(res);
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search