I have an array of objects with a data structure that looks like this:
const fieldArray = [{
"angle": 32.0,
"y": 0,
"x": 0
}, {
"angle": 33.0,
"y": 0,
"x": 10
}, {
"angle": 34.0,
"y": 0,
"x": 20
}, {
"angle": 35.0,
"y": 0,
"x": 30
}, {
"angle": 36.0,
"y": 0,
"x": 40
}] //the array I am using is much larger but follows this format
I have a known x and y value. I would like to write a function that finds the object with the matching x and y value and then returns the corresponding angle value. Here’s what I have so far however after writing it I realize I need to use two for loops. Is there an easier way of doing this like using filter or array find for example?
function getFieldAngleValue (x, y) {
for (let i = 0; i < fieldArray.length; i++){
if(fieldArray[i].x == x && fieldArray[i].y == y ){
let index = i
break
}
}
angle = fieldArray[index].angle;
return angle;
},
2
Answers
You can use array filter method.
This is simpled function code.
You can achieve this using the
Array.find()
method, which makes your code more concise and easier to read. TheArray.find()
method returns the first element in the array that satisfies the provided testing function. If no such element is found, it returnsundefined
.Here’s how you can rewrite your function using
Array.find()
:This code snippet first uses the
Array.find()
method to search through thefieldArray
for an object that matches the providedx
andy
values. If a matching object is found, it returns the correspondingangle
value. If no match is found, it returnsundefined
, but you can customize the behavior for cases where no match is found.This approach eliminates the need for nested loops and improves the readability of your code.