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Javascript – How can filter the sub-arrays inside an array?

This is my array.
I want to get the sub-arrays where the first element is "admin".

const array = [["admin", 1234], ["user", 999], ["admin", 5555]];

The expected output should look like this:

[admin,1234], [admin,5555]
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2

Answers


  1. 0

    You can just use the filter() function. In the callback function you can use destructuring to get the first element of the sub-array, and compare that element to the value "admin":

    const array = [["admin", 1234], ["user", 999], ["admin", 5555]];

const result = array.filter(([k]) => k === 'admin');

console.log(result);
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  2. 0

    We can use the filter method to check if the value of the first index of the subarray is "admin."

    Here is the proposed solution:

    const array = [["admin", 1234], ["user", 999], ["admin", 5555]];
const filteredArray = array.filter(subArr => subArr[0] == "admin");

console.log(filteredArray , ' <<---------- filteredArray');

    Additionally, if the subarray is unordered
    then we can look for the value "admin" and filter out the subarray.

    const array = [["admin", 1234], ["user", 999], ["admin", 5555]];
const filteredArray = array.filter(subArr => (subArr.includes("admin") === true);
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