Question 349863 in Javascript Question posted in
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Javascript – how can I update an array which has a different type and secondary array has different type in typescript

let user: { id: number, name: string }[] = [
    { "id": 0, "name": "ABC" },
    { "id": 1, "name": "XYZ" }
];

let dataList: { id: number, name: string, address: string , pin: string, comment: string}[] = [];

If I want to move the user data array to dataList array how can I do that?

If I use map function then do I need to initialize empty data for other fields for dataList?

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2

Answers


  1. 0

    Yes, I need to initialize empty data.

    Here is a simple example.

    let user: { id: number, name: string }[] = [
    { "id": 0, "name": "ABC" },
    { "id": 1, "name": "XYZ" }
];

let dataList: { id: number, name: string, address: string, pin: string, comment: string }[] = user.map(item => {
    return {
        id: item.id,
        name: item.name,
        address: "",
        pin: "",
        comment: ""
    };
});
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  2. 0

    map return an array, so you simply

    dataList=user.map((x:any)=>({
  id:x.id,
  name:x.name,
  address:...
  ...rest of properties...
})

    In "strict mode", if you don’t want add all the properties with a default value you should use some like

    dataList=user.map((x:any)=>({
  id:x.id,
  name:x.name,
  address:...
  ...not all the properties...
} as { id: number, name: string, 
       address: string , pin: string, 
       comment: string})

    See the implicit convert "as". Generally you use an interface

    export interface dataModel
     { id: number, name: string, 
       address: string , pin: string, 
       comment: string}
     }

dataList:dataModel=user.map((x:any)=>({
  id:x.id,
  name:x.name,
} as dataModel)

    Yes, a "map" if "somelike"

    data=[]
for (let i=0;i<user.length;i++)
   data.push({
       id:user[i].id
       name:user[i].name
   })
return data
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