Question 237774 in Javascript Question posted in
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Javascript – How to delete substring beginning with "#blah" until end?

Assume I want to delete a substring which starts with "#blah" until the end of string. #blah itself should be deleted too.

How can I achieve this? e.g.
var address = document.URL.replace("#blah","");
deletes only the keyword but not the following, remaining part.

If "#blah" is not found in string then nothing should happen.

Tags:

3

Answers


  1. 0

    You can do this with a regex matching blah# and everything that comes after it.

    const myText = "address.com/stuff/things#blah-and-other-stuff";
const blahRegex = /#blah.*$/;
const withoutBlah = myText.replace(blahRegex, "");
console.log(`Before: ${myText}`);
console.log(`After ${withoutBlah}`)
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  2. 0

    How about using a Regex

    /#blah.*$/ will replace the matched pattern and everything afterwards.

    const url1 = "https://example.com/#blah";
const url2 = "https://example.com/#blah/something-else";
const url3 = "https://example.com/";

const result1 = url1.replace(/#blah.*$/, "");
const result2 = url2.replace(/#blah.*$/, "");
const result3 = url3.replace(/#blah.*$/, "");

console.log(result1); // Output: "https://example.com/"
console.log(result2); // Output: "https://example.com/"
console.log(result3); // Output: "https://example.com/"
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  3. 0

    I agree with the other answers that regex is the way to go here.

    If you wish you can also achieve the result using indexOf & substring.

    const removeBlah = (word) => {
    var index = example.indexOf("#blah")
    if(index >=0){
        return example.substring(0,index);
    }   else {
        return word
    }
}

var example = "www.example.com/#blah"
console.log(removeBlah(example))

example = "www.example.com/#blah/page"
console.log(removeBlah(example))

example = "www.example.com/"
console.log(removeBlah(example))
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