Javascript - How to filter out a key from a second level object of a nested array of objects

Einarr
April 29, 2024
101 views
3 votes
4 Answers

I am trying to filter out a key, in this case, count from a nested array of objects.

I have

let test  = [
 {
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
   "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
    "index": 0,
    "value": "Bob",
    "label": "Bob",
    "count": 1
   },
   "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
    "index": 1,
    "value": "Student",
    "label": "Student",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
    "index": 2,
    "value": "BBB",
    "label": "BBB",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
    "index": 3,
    "value": "Orange Duck",
    "label": "Orange Duck",
    "count": 1
   }
  }
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
 }
]

 test = test.filter(item => item[0].options['count']);

but I am getting Cannot read properties of undefined

I am trying to filter out count from all elements of test that have options

desired output is

Thanks

[
 {
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
   "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
    "index": 0,
    "value": "Bob",
    "label": "Bob"
   },
   "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
    "index": 1,
    "value": "Student",
    "label": "Student"
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
    "index": 2,
    "value": "BBB",
    "label": "BBB",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
    "index": 3,
    "value": "Orange Duck",
    "label": "Orange Duck"
   }
  }
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
 }
]

Answers

filter() is used to filter a portion of an array, not to delete nested keys of an object.

The easiest way to achieve your desired result it to:

Loop over each object
If this object has options
Loop over each options
Use delete to delete the count of the current object

const data = [{"id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8", "label": "Sector2", "options": {"62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {"index": 0, "value": "Bob", "label": "Bob", "count": 1 }, "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {"index": 1, "value": "Student", "label": "Student", "count": 1 }, "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {"index": 2, "value": "BBB", "label": "BBB", "count": 1 }, "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {"index": 3, "value": "Orange Duck", "label": "Orange Duck", "count": 1 } } }, {"id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485", "label": "Brown Cow" }, {"id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ", "label": "Red Fish" } ];

for (let i in data) {
    if (data[i]?.options) {
        for (let j in data[i].options) {
            delete data[i].options[j]?.count;
        }
    }
}

console.log(data);

You could destructure the objects and remove unwanted property.

const
    filter = ({ count, ...o }) => Object.fromEntries(Object
        .entries(o)
        .map(([k, v]) => [k, v && typeof v === 'object' ? filter(v) : v])
    ),
    data = [{ id: "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8", label: "Sector2", options: { "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": { index: 0, value: "Bob", label: "Bob", count: 1 }, "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": { index: 1, value: "Student", label: "Student", count: 1 }, c59ea1159f33b91a7f6edc6925be5e373fc543e4: { index: 2, value: "BBB", label: "BBB", count: 1 }, c59ea1159f33b91a7f6edc6925be5e373fc54AAA: { index: 3, value: "Orange Duck", label: "Orange Duck", count: 1 } } }, { id: "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485", label: "Brown Cow" }, { id: "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ", label: "Red Fish" }],
    result = data.map(filter);

 console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

let test  = [
 {
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
   "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
    "index": 0,
    "value": "Bob",
    "label": "Bob",
    "count": 1
   },
   "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
    "index": 1,
    "value": "Student",
    "label": "Student",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
    "index": 2,
    "value": "BBB",
    "label": "BBB",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
    "index": 3,
    "value": "Orange Duck",
    "label": "Orange Duck",
    "count": 1
   }
  }
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
 }
]



test = test.map(o => !o.options ? o : Object.fromEntries(
  Object.entries(o.options).map(([key, {
    count,
    ...rest
  }]) => [
    key, rest
  ])
));

console.log(test)

A generic solution to the OP’s problem does, regardless of the provided data-structure, structurally clone such an object while omitting any property which matches the provided set of to be omitted keys/property-names …

let sampleData = [{
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
    "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
      "index": 0,
      "value": "Bob",
      "label": "Bob",
      "count": 1
    },
    "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
      "index": 1,
      "value": "Student",
      "label": "Student",
      "count": 1
    },
    "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
      "index": 2,
      "value": "BBB",
      "label": "BBB",
      "count": 1
    },
    "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
      "index": 3,
      "value": "Orange Duck",
      "label": "Orange Duck",
      "count": 1
    }
  }
}, {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
}, {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
}];

console.log(
  cloneDataAndIgnoreKeys(
    sampleData,
    new Set(['count']),
  )
);

.as-console-wrapper { min-height: 100%!important; top: 0; }

<script>
function cloneDataAndIgnoreKeys(
  dataSource, ignoredKeys = new Set, dataTarget = {}
) {
  if (Array.isArray(dataSource)) {

    dataTarget = dataSource
      .map(item =>
        cloneDataAndIgnoreKeys(item, ignoredKeys)
      );
  } else if (!!dataSource && (typeof dataSource === 'object')) {

    dataTarget = Object
      .entries(dataSource)
      .reduce((target, [key, value]) => {

        if (!ignoredKeys.has(key)) {
          target[key] =
            cloneDataAndIgnoreKeys(value, ignoredKeys);
        }
        return target;

      }, dataTarget);

  } else {
    dataTarget = dataSource;
  }
  return dataTarget;
}
</script>

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Javascript – How to filter out a key from a second level object of a nested array of objects

Answers