Question 246382 in Javascript Question posted in
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Javascript – How to show double underscore '__' if any object property value is missing

As you can see I am printing object property values but I can’t print double underscore instead of ‘__’ missing property value.

function findAddress(obj){
let object = Object.values(obj);
for(let i = 0; i < obj.length; i++){
    const objects = obj[i];
    if(objects[values] === object[values] == ''){
        return objects.obj[values] = '__' ;
        }
    else if(objects === object){
        object = objects;
     }
}
return object;
}
const output = {street : 10, house : '', society : 'Earth Perfect'};
const res = findAddress(output);
console.log(res);

I am trying to print object property values but, if any property value is missing I want to print double underscore ‘__’ instead of missing value. This program is printing object property value but it didn’t printing missing property value.

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2

Answers


  1. 0

    You can simply achieve this:

    function findAddress(obj){
  for(let property in obj){
    if(obj[property] === ''){
      obj[property] = '__';
    }
  }
  return obj;
}
const output = {street : 10, house : '', society : 'Earth Perfect'};
const res = findAddress(output);
console.log(res);
    Login or Signup to reply.
  2. 0

    You cannot iterate an object (it doesn’t have length property by default and number keys). But you can get an array of an object’s keys and reduce them to a new object with needed transformations:

    const findAddress = obj => 
  Object.keys(obj).reduce((r, key) => (r[key] = obj[key] === '' ? '__' : obj[key], r), {});

const output = {street : 10, house : '', society : 'Earth Perfect'};
const res = findAddress(output);
console.log(res);
    Login or Signup to reply.
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