Question 180940 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – How to terminate gulp unconditionally from within a task?

I want to terminate Gulp without any further action:

gulp.task('watch', function () {
    gulp.watch('…', function quit (cb) {
        // ... totally terminate gulp here, no cleanup required, drop to OS system prompt.
    }
}

I tried throw new Error('ciao') and that would quit the watch but not the outer task loop.

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2

Answers


  1. Chosen as BEST ANSWER
    0

    Not elegant, but what works is process.exit(0);


  2. 0

    You can use the process.exit() functionality, as

    gulp.task('watch', function () {
  gulp.watch('...', function (cb) {
    // Terminate Gulp & exit the task loop
    process.exit();
  });
});
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