Javascript - i need to filter array of object, filteration happend on condition startwith and string contains

Sam
May 31, 2023
182 views
3 votes
4 Answers

This is my array of objects
i need to filter this with name

case one : if i search ‘tali’ filter result from startwith case, same time user enter ‘tali Co OP’ get the result ‘Taliparamba Co Op Hospital’

case two : if i search ‘ath’ get result of ‘Athikkal Saw Mill,Kallai’ and ‘Marhaba Ice Plant Atholi’ beacause Ath contain in ‘Marhaba Ice Plant Atholi’

 test = [{ id: 1, name: 'Taliparamba Co Op Hospital' },
    { id: 1, name: 'Athikkal Saw Mill,Kallai' },
    { id: 1, name: 'Marhaba Ice Plant Atholi' },]

Tags: javascript typescript

Answers

Chosen as BEST ANSWER

let filteredArray = [];
        if (event.target.value.length) {
            const regex = new RegExp(event.target.value.split(' ').join('.*'), 'i');
            this.branchListBuffer = this.branchNameList.filter((data) => data.displayName.toLocaleLowerCase().startsWith(event.target.value.toLocaleLowerCase()));
            if (this.branchListBuffer.length == 0) {
                filteredArray = this.branchNameList.filter(s => regex.test(s.displayName.toLocaleLowerCase()));
                this.branchListBuffer = filteredArray;
            }`enter code here`
        }
        if (event.target.value.length == 0) {
            this.branchListBuffer = this.branchNameList;
        }

i tried this but some case not get

(Edit)

const test = [
      { id: 1, name: 'Taliparamba Co Op Hospital' },
      { id: 1, name: 'Athikkal Saw Mill,Kallai' },
      { id: 1, name: 'Marhaba Ice Plant Atholi' },
    ];

    function search(arr, str) {
      const regexp = new RegExp('\b' + str.split(' ').join('.*?\b'), 'i');
      return arr.filter((item) => regexp.test(item.name));
    }

    console.log(search(test, 'tali'));
    console.log(search(test, 'tali Co OP'));
    console.log(search(test, 'ath'));

 const test = [{ id: 1, name: 'Taliparamba Co Op Hospital' },
    { id: 1, name: 'Athikkal Saw Mill,Kallai' },
    { id: 1, name: 'Marhaba Ice Plant Atholi' },]
    
const myString = "ath"; // your search string goes here
const result = test.filter(eachObject => {
    return eachObject.name.toLowerCase().search(myString) !== -1
})

console.log("result is", result)

I think below line of code should do the job for you

const test = [
    { id: 1, name: 'Taliparamba Co Op Hospital' },
    { id: 2, name: 'Athikkal Saw Mill,Kallai' },
    { id: 3, name: 'Marhaba Ice Plant Atholi' },
];

const searchedStr = 'Ath'
const results = test.filter(obj => 
    obj.name.includes(searchedStr) || 
    obj.name.includes(searchedStr.toLowerCase())
);

console.log(results)

Please let us know how it goes

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Javascript – i need to filter array of object, filteration happend on condition startwith and string contains

Answers