JavaScript: If String Is Not A or B Then

RonnieRoyston
February 7, 2024
131 views
0 votes
2 Answers

How do I achieve this with a single if ? In other words, if(fruit != "apple" || fruit != "orange"){ is not producing the expected result?

fruits.forEach(function(fruit){
  if(fruit != "apple"){ // < ----I want to use a compound OR, or compare multiple strings.
    if(fruit != "orange"){ // <---------I want this nested if gone.
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I'm having problems with
  if(fruit != "apple" || fruit != "orange"){
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

Tags: javascript

Answers

@Pointy points out that:

const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I'm having problems with
  if(fruit != "apple" && fruit != "orange"){ // notice
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

One liners?

const fruits = ['apple', 'orange', 'banana', 'cherry'];
fruits
  .filter(f => f !== 'apple' && f !== 'orange')
  .forEach(f => console.log(`${f} is nor apple nor orange`));

// alternatively
fruits
  .filter(f => !['apple', 'orange'].includes(f))
  .forEach(f => console.log(`${f} is nor apple nor orange`));

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