Javascript Question posted in
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JavaScript: If String Is Not A or B Then

How do I achieve this with a single if ? In other words, if(fruit != "apple" || fruit != "orange"){ is not producing the expected result?

fruits.forEach(function(fruit){
  if(fruit != "apple"){ // < ----I want to use a compound OR, or compare multiple strings.
    if(fruit != "orange"){ // <---------I want this nested if gone.
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I'm having problems with
  if(fruit != "apple" || fruit != "orange"){
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});
Tags:

2

Answers


  1. 0

    @Pointy points out that:

    const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I'm having problems with
  if(fruit != "apple" && fruit != "orange"){ // notice
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});
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  2. 0

    One liners?

    const fruits = ['apple', 'orange', 'banana', 'cherry'];
fruits
  .filter(f => f !== 'apple' && f !== 'orange')
  .forEach(f => console.log(`${f} is nor apple nor orange`));

// alternatively
fruits
  .filter(f => !['apple', 'orange'].includes(f))
  .forEach(f => console.log(`${f} is nor apple nor orange`));
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