Question 220837 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – Is there a way to use the filter function to remove items in the array until a condition is met?

I want to remove the consonants in a string until I get to a vowel. For example the string "glove", the results should be "ove".

This was my attempt but it will only remove the first consonant.

var newStr = str.split("").splice(1, ).join("");
var removeLetter = str.split("").shift();
Tags:

2

Answers


  1. 0

    Well, in order to do something until you need a loop. First, break your input string "glove" into a char array using .split(''), then check for each char whether it matches any of your defined vowels (['a', 'e', 'i', 'o', 'u']). When the first vowel has been found you break the process, put your chars back together using .join() and return your result.

    const isVowel = char =>
  ["a", "e", "i", "o", "u"].includes(char.toLowerCase());

const removeConsonantsUntilVowel = str => {
  let foundVowel = false;

  return str
    .split("")
    .filter(char =>
      !foundVowel
        ? !isVowel(char)
          ? false
          : (foundVowel = true)
        : true
    )
    .join("");
};

const result = removeConsonantsUntilVowel("glove");
console.log(result);
    Login or Signup to reply.
  2. 0

    You can use a function to delete all words until your condition.

    function removeConsonantsUntilVowel(str) {
  const vowels = 'aeiouAEIOU';
  let index = 0;

  for (let i = 0; i < str.length; i++) {
    if (vowels.includes(str[i])) {
      index = i;
      break;
    }
  }

  return str.substring(index);
}

const word = "glove";
const result = removeConsonantsUntilVowel(word);
console.log(result);

    But if you do not want that way, this is other way you can do it.

    const vowels = 'aeiouAEIOU';
let index = 0;
const str2 = "GLOVE"

for (let i = 0; i < str2.length; i++) {
  if (vowels.includes(str2[i])) {
    index = i;
    break;
  }
}
console.log(str2.substring(index))
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search