Javascript - Is this the new way to represent async/await without try-catch block

NAHYAN
September 19, 2024
88 views
0 votes
2 Answers

async function fetchData() {
    const [error, response] = await fetch('https://jsonplaceholder.typicode.com/todos/1')
    if (error) {
        console.log(error);
        return
    }
    
    const [e, data] = await response.json()
    if (e) {
        console.log(e);
        return
    }
    return data
}

fetchData()

I came across a LinkedIn post showing this it the new way to represents async/await without using try-catch block, is this right correct me if its wrong. its not working for me.

Answers

I’ve been using this workaround to avoid try/catch its like error first callback, but it make sense to use try/catch.

async function fetchData() {
  const { error, data } = await fetch(
    "https://jsonplaceholder.typicode.com/todos/1"
  )
    .then(async (res) => {
      const data = await res.json();
      return {
        data,
        error: null,
      };
    })
    .catch((error) => ({
      error,
      data: null,
    }));
  if (error) {
    return;
  }
  return data;
}

fetchData().then(console.log);

use .catch like this:

const { error, data } = await fetch(
  "https://jsonplaceholder.typicode.com/todos/1"
).catch(e => {
 console.log(e);
})

Try a third-party library named await-to-js

import to from 'await-to-js';
async function fetchData() {
    const [error, response] = await to(fetch('https://jsonplaceholder.typicode.com/todos/1'))
    if (error) {
        console.log(error);
        return
    }
    
    const [e, data] = await to(response.json())
    if (e) {
        console.log(e);
        return
    }
    return data
}

Please signup or login to give your own answer.

Click here to cancel reply.

Javascript – Is this the new way to represent async/await without try-catch block

Answers