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Javascript – JS Regex MatchAll with combination of Comma & Semicolon

I’m having a requirement of js regex should return the object from String.

String: 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E'

Output:

{
A: '100 - 200',
B: 'Test & Test2, Tes3',
C: '40',
D: '11 22',
E: 'E 444,55E'
}

I tried with following regex.

const regexp = /([^:]+): ?([^,]*),? ?/g;

But the output was not correct. Value for E is wrong.

{A: '100 - 200', B: 'Test & Test2', Tes3C: '40', D: '11 22', E: 'E 444'}
Tags:

4

Answers


  1. 0

    You could split the string and get parts for the object.

    const
    string = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E',
    parts = string.split(/, (?=[^,]:)/),
    result = Object.fromEntries(parts.map(s => s.match(/([^:]+): (.*)/).slice(1)));

console.log(result);
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  2. 0

    You could use some lookahead:

    const input = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E'

const out = {};
for(const m of input.matchAll(/(?:^|,)s*(S+):s*([^:]+)(?=,s*S+:|$)/g)){
  out[m[1]] = m[2];
}

console.log(out);
    ` Chrome/129
-------------------------------------------------
Alexander  ■ 1.00x | x1000000 404 407 419 423 444
ggg          1.35x | x1000000 546 547 552 554 565
------------------------------------------------- `

    Open in the playground

    const input = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E'


// @benchmark Alexander
const out = {};
for(const m of input.matchAll(/(?:^|,)s*(S+):s*([^:]+)(?=,s*S+:|$)/g)){
  out[m[1]] = m[2];
}
out;

// @benchmark ggg
const
    parts = input.split(/, (?=[^,]:)/);
    Object.fromEntries(parts.map(s => s.match(/([^:]+): (.*)/).slice(1)));
    
/*@skip*/ fetch('https://cdn.jsdelivr.net/gh/silentmantra/benchmark/loader.js').then(r => r.text().then(eval));
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  3. 0

    Similar to other answers, in one functional expression:

    const input = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E'

const result = Object.fromEntries(Array.from(
    input.matchAll(/([^s,:]+)s*:s*([^:]+)(?=,|$)/g), ([, ...pair]) => pair
));

console.log(result);

    If speed is important, then use the traditional exec method:

    const input = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E'

let re = /([^s,:]+)s*:s*([^:]+)(?=,|$)/g, match, result = {};
while (match = re.exec(input)) result[match[1]] = match[2];

console.log(result);
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  4. 0

    The regex that you tried ([^:]+): ?([^,]*),? ? also has a match Tes3, C: 40 which is not correct besides the match for E.

    You get those matches because this part [^,]* does not match a comma, so it will stop when it encounters the first one.

    Also note that when using a pattern like this with negated character classes ([^:]+): ?([^,]*) it can also match just :

    Another version with 2 capture groups:

    b([A-Z]+):s+([^s,][^,]*(?:,(?!s+[A-Z]+:)[^,]*)*)

    The regex in parts match:

    • b A word boundary to prevent a partial word match
    • ([A-Z]+) Capture group 1, match 1+ chars A-Z
    • :s+ Match a colon and 1+ whitespace chars
    • ( Capture group 2
      • [^s,][^,]* Match at least 1 non whitespace char other than a comma followed by 0+ chars other than a comma
      • (?: Non capture group to repeat as a whole
        • ,(?!s+[A-Z]+:) Match a comma when not directly followed by whitespace chars, 1+ chars A-Z and a colon
      • [^,]* Match optional characters other than a comma
      • )* Close the non capture group and optionally repeat it
    • ) Close group 2

    See a regex demo

    const regex = /b([A-Z]+):s+([^s,][^,]*(?:,(?!s+[A-Z]+:)[^,]*)*)/g;
const s = 'A: 100 - 200, B: Test & Test2, Tes3, C: 40, D: 11 22, E: E 444,55E';
const result = Object.fromEntries(
  Array.from(
    s.matchAll(regex),
    m => [m[1], m[2]]
  )
);
console.log(result);
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