Question 258376 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – Loop in Loop Multiple Array in Array using for loop

const listOfNeighbours = [
  ["Canada", "Mexico"],
  ["Spain"],
  ["Norway", "Sweden", "Russia"],
];

for (let i = 0; i < listOfNeighbours.length; i++) {
  for (let j = 0; j < listOfNeighbours[j].length; j++) {
    console.log(`Neighbours : ${listOfNeighbours[i][j]}`);
  }
}

Neighbours : Canada
Neighbours : Spain
Neighbours : Norway

In this question only first ones are printed . How to write all of them to console log

I want like this below in order


Neighbours : Canada
Neighbours : Mexico
Neighbours : Spain
Neighbours : Norway
Neighbours : Sweden
Neighbours : Russia
Tags:

3

Answers


  1. 0

    Your inner loop is only going to listOfNeighbours[j], using j, which is the current iterator. Us i as the index for listOfNeighbors in the inner loopfor (let j = 0; j < listOfNeighbours[i].length; j++) {

    const listOfNeighbours = [
  ["Canada", "Mexico"],
  ["Spain"],
  ["Norway", "Sweden", "Russia"],
];

for (let i = 0; i < listOfNeighbours.length; i++) {
  for (let j = 0; j < listOfNeighbours[i].length; j++) {
    console.log(`Neighbours : ${listOfNeighbours[i][j]}`);
  }
}
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  2. 0

    you can also use flat(), which simplifies the syntax.

    const listOfNeighbours = [
["Canada", "Mexico"],
  ["Spain"],
  ["Norway", "Sweden", "Russia"],
].flat();

for (let i = 0; i < listOfNeighbours.length; i++) {
 
    console.log(`Neighbours : ${listOfNeighbours[i]}`);
  
}
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  3. 0

    It’s not with for loop but you will get the same result:

    const listOfNeighbours = [
  ["Canada", "Mexico"],
  ["Spain"],
  ["Norway", "Sweden", "Russia"],
];
listOfNeighbours
  .flat()
  .forEach(element =>
    console.log(`Neighbours : ${ element }`)
  );
    .as-console-wrapper { min-height: 100%!important; top: 0; }
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