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Looking for a regex that could work in both Javascript and Java.

The whole String should match as long as each capital alphabet follows by a :Y.

All following examples should match in full.

So Any Capital letter followed by a :Y. Like A:Y.
If there is more than 1 pair it is separated by a comma.

S:Y,P:Y,T:Y,A:Y
S:Y,P:Y,T:Y,A:Y,C:Y
S:Y,P:Y,T:Y,A:Y,C:Y,D:Y
A:Y
B:Y
D:Y,F:Y

All the following should never match. Cos 1 or more of them has :N.

S:Y,P:N,T:Y,A:Y
S:Y,P:Y,T:Y,A:Y,C:N
S:Y,P:Y,T:N,A:Y,C:N,D:Y
A:N
B:N
D:Y,F:N

I don’t want to match in negative, like :N doesn’t exist.

^(?!.*:N).+$

Looking for a way to match :Y instead.

Tried the following but this ends up with multiple mini matches which is not what I am looking for.

[SPTA:Y,]+

This could work. But again, this has multiple mini matches.

(?:[A-Z]:Y(?:,|$))+

Could I get some help with this pls.

2

Answers


  1. You could use this regex:

    ^[A-Z]:Y(?:,[A-Z]:Y)*$
    
    • ^: Assert the we’re at the start of the input
    • [A-Z]: Match a capital English letter
    • :Y: Math literally ":Y"
    • (?: )*: repeat the enclosed pattern 0 or more times
    • ,: a literal comma
    • $: Assert we’re at the end of the input.
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  2. Just use this, as all are full lines, just anchor them to beggining or end

    ^[A-Z]:Y(,[A-Z]:Y)*$
    
    • ^ asserts position at start of a line
    • [A-Z] matches a single character in the range between A and Z
    • :Y matches the characters :Y literally.
    • 1st Capturing Group (,[A-Z]:Y)*. * matches the group between zero and unlimited times, as many times as possible.
      • , matches the character ,
      • [A-Z] matches a single character in the range between A and Z.
      • :Y matches the characters :Y literally.
    • $ asserts position at the end of a line.

    This is: groups of one or more [A-Z]:Y separated by , and of arbitrary length.

    See demo.

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