Question 49326 in Javascript Question posted in
A very good W3school tutorial can be found here.

javascript number pattern print

How to print the below pattern using javascript

n = 4

1
2 5
3 6 8
4 7 9 10

I tried the below code but it print the incremental number in row

const pattern = (n) => {
  let count = 1;
  for (let row = 0; row < n; row++) {
    for (let col = 0; col <= row; col++) {
      document.write(count + " ");
      count++;
    }
    document.write("<br/>");
  }
};

pattern(4);

but the expectation is to print incremental number in col

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3

Answers


  1. 0

    You are almost on goal.. you just a small fix: pretty simple and basic

    const pattern = (n) => {
  let count = 1;
  for (let i = 1; i <= n; i++) {
    let row = "";
    let currentNum = count;
    for (let j = 1; j <= i; j++) {
      row += currentNum + " ";
      currentNum += (n - j) ;
    }
    console.log(row);
    count++;
  }
};

pattern(4);

    and as your example
    instead of console.log you can do

    document.write("<br/>");
document.write(row);
count++;
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  2. 0 
    let count = 1;var a={},n=4;
  for (let row = 0; row < n; row++) {
    for (let col = row+1; col <=n; col++) {
        if(!a[col]){
            a[col]='';
        }
      a[col]+= count + ' ';
      count++;
    }
    console.log(a[row+1]);
  }
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  3. 0 
      let arr = [];
  let val = 1;

  for (let i = 0; i < n; i++) {
    arr[i] = [];
    for (let j = 0; j < n - i; j++) {
      arr[i][j] = val;
      val++;
    }
  }

  let output = "";

  for (let i = 0; i < n; i++) {
    for (let j = 0; j <= i; j++) {
      output += arr[j][i - j] + " ";
    }
    output += "n";
  }

  console.log(output);
}

printIncrementalColumn(5);
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