Question 246452 in Javascript Question posted in
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Javascript reduce() on Object.value

Please, help to undestand the problem? Can’t het result – total amount

const objectWithNumbers = {
  a: 10,
  b: 20,
  c: "string",
  d: 12,
};

function sumObjectValues(obj) {
  Object.values(obj).reduce((sum, key) => {
    if (typeof obj[key] === "number") {
      sum += obj[key];
    }
return sum
  }, 0);
}

const result = sumObjectValues(objectWithNumbers);
console.log(result);
//42should be

Tried to use reduce and can’t get result

Tags:

2

Answers


  1. 0

    few errors.

    1. you need to return the value from function
    2. Object.values actually gives the values not the keys
    const objectWithNumbers = {
  a: 10,
  b: 20,
  c: "string",
  d: 12,
};

function sumObjectValues(obj) {
  return Object.values(obj).reduce((sum, val) => {
    if (typeof val === "number") {
      sum += val
    }
return sum
  }, 0);
}

const result = sumObjectValues(objectWithNumbers);
console.log(result);
//42should be

    or you can use Object.keys

    const objectWithNumbers = {
  a: 10,
  b: 20,
  c: "string",
  d: 12,
};

function sumObjectValues(obj) {
  return Object.keys(obj).reduce((sum, key) => {
    if (typeof obj[key] === "number") {
      sum += obj[key];
    }
return sum
  }, 0);
}

const result = sumObjectValues(objectWithNumbers);
console.log(result);
//42should be
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  2. 0

    An one-liner with a ternary operator:

    const objectWithNumbers = {
  a: 10,
  b: 20,
  c: "string",
  d: 12,
};

const sum = Object.values(objectWithNumbers).reduce((sum, val) => typeof val === 'number' ? sum + val : sum, 0);

console.log(sum);
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