I am working with the following string below:
abcdefg^delim^location^delim^123456
And currently have the following regex:
^(.*?)(?:^delim^|$)
The delimiter between values is "^delim^". I am running in to issues however when I try to execute the below code:
var str = 'abcdefg^delim^location^delim^123456'
var regex = /^(.*?)(?:^delim^|$)/
var matches = str.match(regex)
The issue is that my "matches" variable is returning an array of 2 values: "abcdefg^delim^" AND "abcdefg". How can I edit my regex to not capture the first value there? I only want what comes before the first occurrence of "^delim^", which in this case is "abcdefg"
2
Answers
(?:^delim^|$): This is a non-capturing group that matches either ‘^delim^’ or the end of the string (‘$’). This part allows the match to continue beyond the first ‘^delim^’.
Instead you want to use:
(?=^delim^|$): Positive lookahead assertion that ensures the match is followed by ‘^delim^’ or the end of the string (‘$’). However, it doesn’t consume any characters in the match.
Regular Expression:
^(.*?)(?:^delim^|$)
^
: Asserts the start of the string.(.*?)
: A non-greedy capturing group that matches any characters (as few as possible) until the next part of the pattern.(?:^delim^|$)
: A non-capturing group that matches either the delimiter^delim^
or the end of the string $.'abcdefg^delim^location^delim^123456'
Matching Process:
(^)
.(.*?)
captures the characters'abcdefg'
.(?:^delim^|$)
is not yet matched.Resulting Array (matches):
'abcdefg^delim^location^delim^'
(.*?)
:'abcdefg'