Question 136747 in Javascript Question posted in
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Javascript – Regex is not accepting space in between digits

Using this regex: (.*)(EB([s]{0,})[0-9]{7}) to remove white spaces and able to read 7 digits after EB but its not accepting space between digits.

Currently it’s passing value with space after EB and not accepting space in b/w 7 digits.

Input string: EB 67645 89

Using value.replaceAll("s",""); in code.

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2

Answers


  1. 0

    You can try this regex, it should help to solve your problem:

    (.*)(EB)s*(ds*){7}

    By the way you can use regex101 to play with regex, it’s very useful environment when you’re working with regexps.

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  2. 0

    To match the example string you don’t need the capture groups, you can match 7 times a digit preceded by optional whitespace chars (note that it can also match newlines).

    Then you can remove the whitespace chars from this match using replaceAll:

    bEB(?:s*d){7}b

    In Java

    String regex = "\bEB(?:\s*\d){7}\b";

    Regex demo

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