Question 223108 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – regex – multiple line and multiple content

I’m looking for a pattern that match with

    "changes": [
      "5.12.0",
      "5.14.0"
    ],
...
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
...
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],

I’m no expert, I’ve tried maybe 40 or 50 different solutions, here’s my last try:

/"changes": [s*("([0-9](.+))*"(,+))*s*],/

i try this one and it works, ty.

"changes": [s*("([0-9](.+))*"(,+)s )+("([0-9](.+))*"s)],
Tags:

2

Answers


  1. Chosen as BEST ANSWER
    0

    sorry if i dont clarify, i have a json with 3 000k lines, with a big array of object and i want to delete all changes versions of any object.

    the solution is :

    "changes": [s*("([0-9](.+))*"(,+)s*)+("([0-9](.+))*"s*)],

    thank you ! i spend 4 hours this morning and i found some minutes after asking :(


  2. 0

    I would do it in two steps:

    1. Search for the list of versions between the brackets after "changes":

      /"changes":s*[s*([^]]+)s*]/gs : https://regex101.com/r/XHaxJ0/1

    2. For each match, you’ll get the list of versions in the capturing group 1:

      "4.4",
      "5.0.0",
      "5.10.1"

      You can then extract each version with /[d.]+/g : https://regex101.com/r/XHaxJ0/2

    The Javascript code:

    const input = `    "changes": [
      "5.12.0",
      "5.14.0"
    ],
...
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
...
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],`;

const regexChangesContent = /"changes":s*[s*([^]]+)s*]/gs;
const regexVersion = /[d.]+/g;

// To fill with the found versions in the changes arrays.
let versions = [];

let matchChangesContent,
    matchVersion;

while ((matchChangesContent = regexChangesContent.exec(input)) !== null) {
  while ((matchVersion = regexVersion.exec(matchChangesContent[1])) != null) {
    versions.push(matchVersion[0]);
  }
}

console.log(versions);

    EDIT since question has changed

    As you just want to delete the "changes" entries, I would do the
    following:

    const input = `    "changes": [
      "5.12.0",
      "5.14.0"
    ],
    "date": "01.01.2023",
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
    "property": "value",
    "should_stay": true,
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],`;

const regexChanges = /"changes":s*[s*[^]]+s*]s*,/gs;

console.log(input.replace(regexChanges, ''));
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