Question 200543 in Javascript Question posted in
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Javascript – Regular expression which matches a function name and its parentheses only when there is content inside

Inside of the parentheses there will be a web link which is a string between single quotes.

The name of the function will always be the same.

For example if I have my_func('https://old.reddit.com') the string my_func( and ) should be matched and 'https://old.reddit.com' should not.

The best thing I can come up with is my_func((?=[^)]+)).

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2

Answers


  1. 0

    You could use lookbehind and lookahead
    and match anything that is not a quote (one or more times) until a closing quote and closed brace:

    const getFnArg = (str) => str.match(/(?<=bmy_func(['"`])[^'"`]+(?=['"`]))/)?.[0];
console.log(getFnArg(`my_func('https://old.reddit.com')`))  // "https://old.reddit.com"
console.log(getFnArg(`my_func('whatever')`))  // "whatever"
console.log(getFnArg(`my_func(noquotes)`))    // undefined
console.log(getFnArg(`my_func('')`))          // undefined
console.log(getFnArg(`my_func()`))            // undefined

    Regex1010.com demo

    Or a simpler example without lookbehind/ahead:

    const getFnArg = (str) => str.match(/bmy_func(['"`]([^'"`]+)['"`])/)?.[1];
console.log(getFnArg(`my_func('https://old.reddit.com')`))  // "https://old.reddit.com"
console.log(getFnArg(`my_func('whatever')`))  // "whatever"
console.log(getFnArg(`my_func(noquotes)`))    // undefined
console.log(getFnArg(`my_func('')`))          // undefined
console.log(getFnArg(`my_func()`))            // undefined
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  2. 0

    You can use .+?.

    my_func(.+?)

    This will match your static text, and allow for any value within the opening and closing parentheses.

    The ? will modify the +, making it a lazy-quantifier.
    This is in the case you have text with more than one my_func match, the balanced parenthesis will be matched, and not the adjacent match’s.

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