Question 205465 in Javascript Question posted in
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Javascript: trim off stars or space at the end

I have string which can end either with " *" or " **" or just without space and star.
I have to trim of any space or stars at the end of the string, but I can’t get it to work

trimStarsOff(strWithStars: string): string {
    const returnStr = strWithStars;
    if (strWithStars.includes('*')) {
      const test = strWithStars.replace(' \*$', '');
      cy.log(`test ${test}`);
    }
    return returnStr;
}

The stars remain in my case:

test "Some words test *"

test "Other words test2 *"

What do I miss?

Tags:

3

Answers


  1. 0

    First, use a regular expression literal instead of a string. Also, use + to allow one or more asterisks to be replaced.

    const trimStarsOff = s => s.replace(/ *+$/, '');
console.log(trimStarsOff('Some words test *'));
console.log(trimStarsOff('Test ***'));
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  2. 0

    You’re trying to use a regex in a string instead of just using the /regex/ format (technically you could also use the RegExp constructor with a string). You also don’t need to check if you need to replace, just attempt a replacement and if you get the input echoed as the output, that’s fine.

    function trimStarsOff(strWithStars) {
    return strWithStars.replace(/ *+$/, '');
}

console.log(trimStarsOff("foo bar"));
console.log(trimStarsOff("banana sandwich *"));
console.log(trimStarsOff("corn on the cob **"));
console.log(trimStarsOff("stack overflow"));
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  3. 0

    If you want to have it universal with any number of spaces and stars:

    const log = str => console.log(JSON.stringify(str));

function trimStarsOff(strWithStars) {
    return strWithStars.replace(/[*s]+$/, '');
}

log(trimStarsOff("foo bar"));
log(trimStarsOff("banana sandwich *"));
log(trimStarsOff("corn on the cob * *"));
log(trimStarsOff("stack overflow  *** *"));
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