JS: How to search object for presence of fields based on logical conditions in array? - Javascript

gkeenley
April 5, 2023
148 views
3 votes
3 Answers

I have the following JS object:

let obj = {
    b: 1,
    c: 1,
    d: 2
}

I want to write a function that takes an input array and checks whether the fields listed in this array are present in obj, but I want to have logic in the conditions. So something like

arr = ['b', 'c' || 'd']   (returns true if obj has an entry for `b`, and for either `c` or `d`)

arr = ['c' && 'd']   (returns true only if obj has entries for both `c` and `d`)

so in my function I imagine writing a condition like

return arr.forEach(condition => object[condition])

How can I approach this?

Answers

You can do something like this:
Write a finction like the checkFields function takes in the object, and a string representing the condition you want to check for example: "a||b" or "a&&b" or "a",
it’s gonna split the string by || and && and check for the conditions and return true/false based on wether the condition istrue or not.
Next the calcResult function will take an array like ["a||b", "a"] and pass each of the items of it to the checkFields function and return true if all of the results are true.

const checkFields = (obj, condition) => {
  let result = false;
  if (condition.includes("||")) {
    const [field1, field2] = condition.split("||");
    if (obj.hasOwnProperty(field1) || obj.hasOwnProperty(field2)) {
      result = true;
    } else result = false;
  } else if (condition.includes("&&")) {
    const [field1, field2] = condition.split("&&");
    if (obj.hasOwnProperty(field1) && obj.hasOwnProperty(field2)) {
      result = true;
    } else result = false;
  } else {
    if (obj.hasOwnProperty(condition)) {
      result = true;
    } else result = false;
  }

  return result;
};


const obj = {
  b: 1,
  c: 1,
  d: 2
};

const arr1 = ['b', 'c', 'd||b', 'a||f'];
const arr2 = ['b', 'c&&b', 'd&&b', 'a||d'];
const calcResult = (array) => array.reduce((acc, item) => acc && checkFields(obj, item), true);


console.log(calcResult(arr1));
console.log(calcResult(arr2));

Build up rules programmatically and evaluate them.

/* library code */
const hasProp = prop => obj =>
  prop in obj;
  
const or = (...conditions) => obj =>
  conditions.some(condition => condition(obj));

const and = (...conditions) => obj =>
  conditions.every(condition => condition(obj));
  
const apply = rules => obj =>
  rules.map(fn => fn(obj));
/* /library code */

const arr = [
  hasProp("a"), // false
  hasProp("b"), // true
  or(hasProp("a"), hasProp("b")), // true
  or(hasProp("a"), hasProp("z")), // false
  and(hasProp("c"), hasProp("d")), // true
  and(hasProp("a"), hasProp("d")), // false
  and(hasProp("b"), hasProp("c"), hasProp("d")), // true
  and(or(hasProp("a"), hasProp("b")), and(hasProp("d"), hasProp("d"))) // true
];

const checkAllRules = apply(arr);

console.log(checkAllRules(obj));

<script>
//set up data
let obj = {
    b: 1,
    c: 1,
    d: 2
}
</script>

This can be extended with any amount of more checks (like if a property has a specific value, if it is a Date object) and operators (like not to invert a result):

/* library code */
const hasProp = prop => obj =>
  prop in obj;
  
const hasValue = (prop, value) => obj =>
  obj[prop] === value;

const isDateObject = obj =>
  obj instanceof Date;
  
const or = (...conditions) => obj =>
  conditions.some(condition => condition(obj));

const and = (...conditions) => obj =>
  conditions.every(condition => condition(obj));

const not = rule => obj => 
  !rule(obj);
  
const apply = rules => obj =>
  rules.map(fn => fn(obj));
/* /library code */

const arr = [
  hasValue("b", 1), // true
  hasValue("b", 7), // false
  isDateObject, //false
  not(hasProp("a")), //true
  or(hasValue("b", 7), hasValue("d", 2)), // true
  and(hasValue("c", 1), not(isDateObject)), // true
];

const checkAllRules = apply(arr);

console.log(checkAllRules(obj));

<script>
//set up data
let obj = {
    b: 1,
    c: 1,
    d: 2
}
</script>

You are going to have to write yourself some sort of rules engine that is able to process logical checks. Below is a basic idea of using objects.

function basicIdea(rules, obj) {

  const checksFns = {
    and: arr => arr.every(checkIt),
    or: arr => arr.some(checkIt),
  };

  const hasKey = key => key in obj;

  const checkIt = item => {
    if (typeof item === 'object') {
      const {
        op,
        checks
      } = item;

      return checksFns[op](checks);
    }

    return hasKey(item);
  }

  return checkIt(rules);
}

var obj1 = {
  a: 1,
  b: 1,
  c: 1
};

console.log('check and good', basicIdea({
  op: 'and',
  checks: ['a', 'b', 'c']
}, obj1));

console.log('check and bad', basicIdea({
  op: 'and',
  checks: ['a', 'b', 'd']
}, obj1));

console.log('check or good', basicIdea({
  op: 'or',
  checks: ['d', 'a']
}, obj1));

console.log('check or bad', basicIdea({
  op: 'or',
  checks: ['d', 'e']
}, obj1));

console.log('check and or good', basicIdea({
    op: 'and',
    checks: ['a', {
      op: 'or',
      checks: [
        'b',
        'c'
      ]
    }],
  },
  obj1));
  
  console.log('check and or bad', basicIdea({
    op: 'and',
    checks: ['a', {
      op: 'or',
      checks: [
        'd',
        'e'
      ]
    }],
  },
  obj1));

Please signup or login to give your own answer.

Click here to cancel reply.

JS: How to search object for presence of fields based on logical conditions in array? – Javascript

Answers