Question 53134 in Javascript Question posted in
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Remove last 2 digits from the array members if the number is more than 2 digit – Javascript

I have an array that consists of multiple elements so what I want to do is remove the last two digits from the array element if the array element consists of 3 or 4 digits then remove the last two digits from it. and if the element is 1 or 2 digits then it will remain the same.

var test =[ 2, 45,567, 3, 6754];

Then the output that I need is :

[ 2, 45, 5, 3, 67];

I have tried this

test.forEach(function(element, index) {    test[index] = element.slice(1, -2); });

But this will remove the single digits element to blank

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2

Answers


  1. 0

    Solution you wrote would not work at all, because u try to slice values with type number.

    Try this:

    test.forEach(function(element, index) {    test[index] = String(element).length > 2 ? +String(element).slice(0, -2) : test[index]});
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  2. 0

    You could divide the value by 100 and take the integer value, if necessary.

    const
    data = [2, 45, 567, 3, 6754],
    result = data.map(v => v >= 100 ? Math.floor(v / 100) : v);

console.log(result);
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