Question 10965 in Jquery Question posted in
The official Jquery Api Documentation can be found here.

access value from dynamic json array in javascript – Jquery

I have a result from an api call

var result = [
    {
        "m1": "State"
    },
    {
        "m2": "Occupation"
    },
    {
        "m3": "Qualification"
    },
    {
        "m4": "Salary"
    },
    {
        "m5": "Age"
    },
    {
        "m6": "Status"
    }
]

I want to be able to grab each value with $.each loop but can’t seem to figure it out.
Here is my code so far.

var meta = $.parseJSON(result)
$.each(meta, function(index, value){
    console.log(value)
})

The question is how can I log these values "State" and "Occupation", "Qualification", "Salary", "Age" and "Status"?

I know one can’t do value."m"+index+1

Please point me the right way.

Tags:

2

Answers


  1. 0

    You could take a flat array of all values of nested objects.

    const
    data = [{ m1: "State" }, { m2: "Occupation" }, { m3: "Qualification" }, { m4: "Salary" }, { m5: "Age" }, { m6: "Status" }],
    result = data.flatMap(Object.values);

console.log(result);
    Login or Signup to reply.
  2. 0

    If you are using js then it will be very easy to iterate values

    var result = [
  {
    m1: 'State',
  },
  {
    m2: 'Occupation',
  },
  {
    m3: 'Qualification',
  },
  {
    m4: 'Salary',
  },
  {
    m5: 'Age',
  },
  {
    m6: 'Status',
  },
];

for (var i = 0; i < result.length; i++) {
  //get the key of the object
  var key = Object.keys(result[i])[0];
  //get the value of an object
  var value = result[i][key];
  console.log(value);
}
    //jquery
$.each(result, function (index, obj) {
  var key = Object.keys(obj)[0];
  var value = obj[key];
  console.log(value);
});

//dynamic function to iterate array
function iterateArray(array) {
  $.each(array, function (index, obj) {
    $.each(obj, function (key, value) {
      console.log(value);
    });
  });
}

    I hope this will be helpful you just need to pass array to this function

    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search