Question 37237 in Jquery Question posted in
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Remove last dots from characters in jquery

How to remove only the last dots in characters in jquery?

Example:

1..

1.2.

Expected result:

1

1.2

My code:

var maskedNumber = $(this).find('input.CategoryData');

var maskedNumberValue = $(maskedNumber).val().replace(/[^0-9.]/g, '').replace('.', 'x').replace('x', '.').replace(/[^d.-]/g, '');

console.log(maskedNumberValue.slice(0, -1))

How do I solve this problem? Thanks

Tags:

5

Answers


  1. 0

    You can use regex replace for that:

    function removeLastDot(value) {
  return value.replace(/.*$/, '')
}

console.log(removeLastDot('1..'))
console.log(removeLastDot('1.2.'))

    In the example I use .*$ regex:

    • $ – means that I want replace at the end of string
    • .* – means that I want to match any number for . symbol (it is escaped cause . is special symbol in regex)
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  2. 0

    You can traverse the string with forEach and store the last index of any number in a variable. Then slice up to that variable.

    let lastDigitIndex = 0;
for (let i = 0; i < str.length; i++) {
   let c = str[i];
   if (c >= '0' && c <= '9') lastDigitIndex = i;
};
console.log(str.slice(0, lastDigitIndex-1));

    This will be an optimal solution.

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  3. 0

    Add replace(/.*$/g, '') to match one or more dots at the end of the string.

    So your code would be like this:

    var maskedNumberValue = $(maskedNumber).val().replace(/[^0-9.]/g, '').replace('.', 'x').replace('x', '.').replace(/[^d.-]/g, '').replace(/.*$/g, '');
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  4. 0

    maybe this can help.

    var t = "1...";
    while (t.substr(t.length - 1, 1) == ".") {
      t = t.substr(0,t.length - 1);
    }
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  5. 0 
    import re
s = '1.4....'
# reverse the string
rev_s =  s[::-1]
# find the first digit in the reversed string
if first_digit := re.search(r"d", rev_s):
    first_digit = first_digit.start()
    # cut off extra dots from the start of the reversed string
    s = rev_s[first_digit:]
    # reverse the reversed string back and print the normalized string
    print(s[::-1])

1.4
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