How to Convert cobal statement to Json

i have to convert cobal statement to json

import re
import json

def extract_cursor(cobol_statement):
    pattern = r"MODIFY MAP (?: CURSOR|TEMP|FOR|PERM|CURSOR)?(?:CURSOR)?(?: AT)?(?: FIELD)?(?: DFLD)?s+([w-]+)(?!()"
    action_regex = re.compile(pattern, re.IGNORECASE)
    action_match = action_regex.search(cobol_statement)
    if action_match:
        cursor_value = action_match.group(1)
        if cursor_value.upper() != "FIELD" and cursor_value.upper() != "DFLD":
            result = {
                "cursor": cursor_value,
                "for": None,
                "attributes": None
            }
            return result
    return None

# Example COBOL statements
cobol_statement1 = "MODIFY MAP TEMP CURSOR AT NBS-DS-01"
cobol_statement2 = "MODIFY MAP CURSOR NBS-DS-01"
cobol_statement3 = "MODIFY MAP FOR FIELD NBS-DS-01"
cobol_statement4 = "MODIFY MAP PERM NBS-DS-01"

# Extract cursor from each COBOL statement
cursor_info1 = extract_cursor(cobol_statement1)
cursor_info2 = extract_cursor(cobol_statement2)
cursor_info3 = extract_cursor(cobol_statement3)
cursor_info4 = extract_cursor(cobol_statement4)

# Convert results to JSON format
json_result1 = json.dumps(cursor_info1, indent=4)
json_result2 = json.dumps(cursor_info2, indent=4)
json_result3 = json.dumps(cursor_info3, indent=4)
json_result4 = json.dumps(cursor_info4, indent=4)

print(json_result1)
print(json_result2)
print(json_result3)
print(json_result4)

my third statement have wrong output please some one help i need the out put like
{
"cursor": "NBS-DS-01",
"for": null,
"attributes": null
}