Question 110400 in Json Question posted in
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how to get json property name

I have a class like following:

public class Client {
    [JsonProperty("first_name")]
    public string FirstName { get; set; }
    [JsonProperty("last_name")]
    public string LastName { get; set; }
}

using the following code I can get the properties and values in a dictionary of that class object:

var propertyValuesByName = client.GetType().GetProperties()
        .Where(pi => pi.PropertyType == typeof(string))         
        .Select(pi => new { Val = (string) pi.GetValue(client), Name = pi.Name })
        .ToDictionary(pi => pi.Name, pi => pi.Val);

so the dictionary contains property name as key and the property value as value. But what I want is, get the dictionary which key will be the object JsonProperty name instead of the real property name, means instead of "FirstName" I want "first_name" as key. How can I modify the above code to achieve this?

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3

Answers


  1. 0

    Use some more reflection to ger info from custom attribute:

    .Select(pi => new 
{ 
    Val = (string) pi.GetValue(client), 
    Name = pi.GetCustomAttribute<JsonPropertyAttribute>()?.PropertyName ?? pi.Name
})

    Or :

    .Select(pi => new 
{ 
    Val = (string) pi.GetValue(client), 
    Name = (pi.GetCustomAttribute(typeof(JsonPropertyAttribute)) as JsonPropertyAttribute)?.PropertyName ?? pi.Name
})

    Also note that if your object contains only string you can deserialize directly to Dictionary<string, string>.

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  2. 0

    I guess it’s similar to the problem exposed in this thread :
    How to get Json Property name using reflection in C#

    If it’s not mandatory for you to access object using reflection, you can just deserialize a Json to a Dictionary<string,string> like this :

    var values = JsonConvert.DeserializeObject<Dictionary<string, string>>(json);

    and then get the keys out of it using values.Keys.
    Hope this helps

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  3. 0

    To get the property name of a JSON object in C#, you can use the nameof operator. For example, given the following JSON object:

    {
  "name": "John Smith",
  "age": 30,
  "city": "New York"
}

    You can use the nameof operator to get the property names like this:

    string name = nameof(jsonObject.name);  // "name"
string age = nameof(jsonObject.age);   // "age"
string city = nameof(jsonObject.city); // "city"

    Note that the nameof operator only works with compile-time constants, so it will not work with dynamically generated property names.

    Alternatively, you can use the JsonPropertyAttribute to specify the property name in the JSON object. For example:
    public class Person

    {
  [JsonProperty("name")]
  public string Name { get; set; }

  [JsonProperty("age")]
  public int Age { get; set; }

  [JsonProperty("city")]
  public string City { get; set; }
}

    you can then use reflection to get the property names like this:
    var person = new Person { Name = "John Smith", Age = 30, City = "New York" };

    foreach (var property in person.GetType().GetProperties())
{

  var jsonPropertyAttribute = property.GetCustomAttribute<JsonPropertyAttribute>();
  if (jsonPropertyAttribute != null)
  {
    string propertyName = jsonPropertyAttribute.PropertyName;
  }
}
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