Question 111000 in Json Question posted in
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Inserting String variable into JSON which is in a form of String

I have a JSON payload saved as a String

String jsonBody = “{n”
            + ” “example“: {n”
            + ”  “example“: [n”
            + ”   {n”
            + ”    “example“: 100,n”
            + ”    “this_is_example_json_key“: “this_is_example_json_value“,n”

I created that by copying body from i.e Postman into

String jsonBody = "here I pasted the body";

Unfortunately I cannot have everything hardcoded there, so I have to change some values to variables. The JSON in postman looks like:

"this_is_example_json_key":"x"

And so on. Let’s assume that:

String x = “this_is_example_json_value“;

If I just replace it like

+ ” “this_is_example_json_key“: “ + x + “,n”

or something like that, the value in the body will be just this_is_example_json_value, where I need "this_is_example_json_value" (the "" marks are part of the value).

So the question is, how to set up those + / " in the String, so in the end in the value of the JSON I will end up with the value inside " ".

I’ve tried to play with the " / + but nothing of those were working. Variable must be passed with those " " because otherwise, the API is sending back an error.

Tags:

3

Answers


  1. 0

    you can use an extra " " "

        String x = "this_is_example_json_value";

    String jsonBody = "{n"
            + ""example": {n"
            + "  "example": [n"
            + "  {n"
            + " "example": 100,n"
            + ""this_is_example_json_key":" + """ + x + """ + "n }"
            +"n  ]n   }n    }";

    in this case you will get a json string

    {
  "example": {
    "example": [
      {
        "example": 100,
        "this_is_example_json_key": "this_is_example_json_value"
      }
    ]
  }
}
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  2. 0

    Don’t try to build up JSON using strings. Use a proper JSON parser.

    import org.json.JSONException;
import org.json.JSONObject;

public class Eg {
    public static void main(String[] args) throws JSONException {
        String x = "this_is_example_json_value";
        JSONObject example = new JSONObject();
        example.put("this_is_example_json_key", x);
        System.out.println(example.toString());
    }
}

    Which outputs:

    {"this_is_example_json_key":"this_is_example_json_value"}

    With no messing around wondering what needs to be escaped.

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  3. 0

    Since java 15, if you want only use the string, you can also do in this way:

    int this_is_example_json_value= 100;
String json = """
{
    "this_is_example_json_key":  %d
}
""".formatted(this_is_example_json_value);

    Here the official jep.

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