Question 108860 in Json Question posted in
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Json – dictionary from different lists python 3

I have the following lists:

list1 = ["Hulk", "Flash", "Tesla"]
list2 = ["green", "23", "thunder"]
list3 = ["Marvel", "DC_comics", "0.0"]

and I would like to create a dictionary like this one:

{
    "eo:dict": [
        {"name": "Hulk", "color": green, "company": Marvel},
        {"name": "Flash", "color": red, "company": DC_comics},
        {"name": "Tesla", "color": thunder, "company": 0.0},
    ]
}

that has to be appended in a specific position within a json file I’m creating.

I tried in this way:

keys = ["name", "company", "colours"]
eo_dict = dict(zip(keys, name,company, color))

but I got the error "_ValueError: dictionary update sequence element #0 has length 3; 2 is required_"

Could anybody give me some hints?

Tags:

2

Answers


  1. 0

    You can use this code to get the expected output:

    list1 = ['Hulk', 'Flash', 'Tesla']
list2 = ['green', '23', 'thunder']
list3 = ['Marvel', 'DC_comics', '0.0']
keys = ['name', 'color', 'company']

out = list(dict(zip(keys, values)) for values in zip(list1, list2, list3))

    Output:

    >>> out
[{'name': 'Hulk', 'color': 'green', 'company': 'Marvel'},
 {'name': 'Flash', 'color': '23', 'company': 'DC_comics'},
 {'name': 'Tesla', 'color': 'thunder', 'company': '0.0'}]

    To export as JSON:

    import json

jd = json.dumps([{'eo:dict': out}], indent=4)
print(jd)

# Output
[
    {
        "eo:dict": [
            {
                "name": "Hulk",
                "color": "green",
                "company": "Marvel"
            },
            {
                "name": "Flash",
                "color": "23",
                "company": "DC_comics"
            },
            {
                "name": "Tesla",
                "color": "thunder",
                "company": "0.0"
            }
        ]
    }
]
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  2. 0

    You should try this one,

    keys = ["name", "age", "location"]
values = ["John", 28, "New York"]

my_dict = {k:v for k, v in zip(keys, values)}

print(my_dict)

    The output is like

    {‘name’: ‘John’, ‘age’: 28, ‘location’: ‘New York’}

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