Question 15242 in Laravel Question posted in
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Laravel testing assertJsonMissing does not work for only key. why?

I’m working on a tdd project where I simply want to make sure that the password is not returned by mistake. here is the test I wrote.

public function testInfoMethodJsonStructure() {
    $user = User::factory()->create();

    $response = $this
        ->actingAs($user)
        ->get('/api/profile/info');

    $response->assertStatus(200);

    $response->assertJsonStructure(['name', 'fullname', 'email']);

    $response->assertJsonMissing(['password']); // this passes
    $response->assertJsonMissing(['password' => $user->password]); // this does not pass
}

I know for a fact that password is being returned but why does the assertJsonMissing does not work when I only pass the key? if it’s not used for that, what is the correct way to check that a data key is missing?

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2

Answers


  1. 0

    Actually assertJsonMissing is for test key, not value!
    You can make a special method for this problem or maybe see this:
    https://laravel.com/docs/10.x/http-tests#assert-json-fragment

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  2. 0

    assertJsonMissing(array $data) tries to find $data whithin the json you returned.

    The difference between assertJsonMissing(['password']) and assertJsonMissing(['password' => 'something']) is the following:

    • assertJsonMissing(['password']) tries to find {"0": "password"} in your json if the json returned is an object.
    • assertJsonMissing(['password' => 'something']) tries to find {"password": "something"} inside the returned json object.

    Here are a couple of alternatives.

    • assertJsonMissingPath('password').
    • Fluent json assertions.
    $response
    ->assertJson(fn (AssertableJson $json) =>
        $json->hasAll(['name', 'fullname', 'email'])
            ->missing('password')
    );
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