Question 15964 in Laravel Question posted in
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Undefined array key but with dd() works – Laravel

I’ve done a query at Laravel and to check result content, I’ve used dd, but, for some reason, when I remove the dd(), it throws an exception sayint "Undefined array key 0". However, with dd DO find the key.

Code is this:

public function getFormatosArticulo(Articulo $articulo){
    $formatoRaw = Formato::where('articulo_id', '=', $articulo->id)->get();
    dd($formatoRaw[0]);
    $formato = $formatoRaw[0];
    return $formato;
}

And dd output is this:

dd output

Tags:

2

Answers


  1. 0

    The reason this happens is that dd stands for “dump and die” so your first iteration goes through but you don’t check the rest because you use die(). A solution to this can be as simple as:

    public function getFormatosArticulo(Articulo $articulo) {
    $formatoRaw = Formato::where('articulo_id', '=', $articulo->id)->get();
    if ($formatoRaw) {
        $formato = $formatoRaw[0];
        return $formato;
    }
}

    Since you are only interested for the [0] position though a similar approach would be:

    public function getFormatosArticulo(Articulo $articulo) {
    $formatoRaw = Formato::where('articulo_id', '=', $articulo->id)->first();
    if ($formatoRaw) {
        return $formatoRaw;
    }
}
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  2. 0

    I guess you are calling getFormatosArticulo function for multiple times, and passed not exists id into it. The get() function will always return a empty collection even if no data matched.

    Can you test your function use code below and check if id does exists or not?

    public function getFormatosArticulo(Articulo $articulo){
    try {
        $formatoRaw = Formato::where('articulo_id', '=', $articulo->id)->get();
        $formato = $formatoRaw[0];
        return $formato;
    catch (Exception $e) {
        dd($articulo->id); // i guess there is no articulo_id equal this in formato table.
    }
}
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