Question 233081 in Mongodb Question posted in
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how we can search via variable in mongodb in node.js

exports.findByTable = (req, res) => {
 console.log(req);
 const table = req.params.table;
 const text = req.params.text;
 Employee.find({[req.params.table]: "/.*"+[req.params.text]+".*/i"})
.then(data => {
  if (!data)
    res.status(404).send({ message: "Not found Employee with id " +[req.params.text]});
  else res.send(data);
  })`your text`
.catch(err => {
  res
    .status(500)
    .send({ message: "Error retrieving Employee with id=" + [req.params.text] });
});
};

i want to search the data by table name coming from request and the search word that is coming from request and i want to use where clause `

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2

Answers


  1. 0

    You can create a filter object then set it’s properties and values like so:

    const filter = {};
filter[req.params['table']] = './*' + req.params['text'] + '.*/i';;

    Then just pass the filter object into the model.find() like so:

    Employee.find(filter){...};
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  2. 0

    To search using a variable in MongoDB with Node.js, you’ll want to use regular expressions to achieve that "LIKE" behavior.

    Here’s a tweak to your code:

    exports.findByTable = (req, res) => {
  const table = req.params.table;
  const text = req.params.text;
  
  const query = {};
  query[table] = { $regex: new RegExp(text, 'i') }; // i flag for case-insensitive

  Employee.find(query)
    .then(data => {
      if (!data.length) {
        res.status(404).send({ message: `No results found for ${text} in ${table}` });
      } else {
        res.send(data);
      }
    })
    .catch(err => {
      res.status(500).send({ message: "Error retrieving data" });
    });
};

    This uses the $regex operator to perform a case-insensitive search based on the table and text you’ve received.

    Remember, MongoDB’s $regex might not be super performant on large datasets, so consider using indexing and other optimization techniques if needed.

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