Question 117879 in Mongodb Question posted in
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Mongodb Populate is not populating document in Node.js

I am using typegoose and my Query and QueryRule models are as below.

export class Query {
  @prop()
  queryRule: Ref<QueryRule>;
}

export class QueryRule {
  @prop()
  condition: Condition;

  @prop()
  rules: Ref<QueryRule | ChildRule>[];
}

I am using the following query to populate.

await QueryModel.findById(queryId).populate('queryRule');

My Query Document is as below.

{"_id":{"$oid":"6283d73baffa60c38af8c2f0"},"name":"test","queryRule":{"$oid":"6287c8f0e3ab4b5dd7238ef3"}}

My QueryRule Document is as below.

{"_id":{"$oid":"6287c8f0e3ab4b5dd7238ef3"},"condition":1,"rules":[],"__v":0}

But when I access condition and rules of QueryRule using populate query. I am getting undefined even though values exist in that document.

What am I doing wrong here?

Tags:

3

Answers


  1. Chosen as BEST ANSWER
    0

    I needed 2 things for this.

    1. First is I was missing { ref: () => QueryRule }
    2. Then in populate I had to pass model like this { path : 'queryRule', model: QueryRuleModel }
    export class Query {
  @prop({ ref: () => QueryRule })
  queryRule: Ref<QueryRule>;
}

    let query: Query = await QueryModel
      .findById(queryId)
      .populate({ path : 'queryRule', model: QueryRuleModel });

  2. 0 
    @prop({
  ref: () => QueryRule | ChildRule,
  required: true
})
rules: Ref<QueryRule | ChildRule>[];
    Login or Signup to reply.
  3. 0

    Your issue seems to be that you are missing the required option ref, see Reference other Classes from the Typegoose Documentation.

    In your case your code should look more like:

    export class Query {
  @prop({ ref: () => QueryRule })
  queryRule: Ref<QueryRule>;
}

export class QueryRule {
  @prop()
  condition: Condition;

  //@prop({ ref: () => QueryRule })
  //rules: Ref<QueryRule | ChildRule>[];
}

    As for Ref<QueryRule | ChildRule>[], you will either have to limit it to one on the 2 possibilities or use discriminators, see Non-Nested Discriminators from the Typegoose Documentation.

    Also as a small side-note, if your condition: Condition is not also a typegoose class, it will become Mixed, which is basically a any type at runtime in mongoose.

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