Question 20610 in Mysql Question posted in
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How can I do this query in sequelize – Mysql

SELECT * 
FROM item_master 
WHERE project_id IN (SELECT id FROM project_master 
                     WHERE workspace_id in (SELECT id FROM workspace_master 
                                            WHERE company_id = 4));

How can I do this mysql query in sequelize – node js without using raw query?

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2

Answers


  1. Chosen as BEST ANSWER
    0 
    const item = await Item.findAll({
    where: {
        status: { [Op.ne]: 99 },
        '$project.workspace.company_id$': { [Op.eq]: req.user.companyId }
    },
    include: {
        model: Project,
        as: 'project',
        attributes: ['id'],
        include: {
            model: Workspace,
            as: 'workspace',
            attributes: ['id', 'companyId'],
            where: {
                companyId: req.user.companyId
            },
        },
    }
})

    This is working as I want.

    '$project.workspace.company_id$': { [Op.eq]: req.user.companyId }


  2. 0

    If your model structure is like item_master has many project_master, and project_master has many workspace_master, then the following sequelize query will be applied with async/await.

    As I edited my answer. As you said in comment, you have model structure like workspace has many projects and projects has many items. Then Sequelize query will be like:

        const getResult = async (workpace_id, company_id = 4) => {
      const result = await workspace_master.findAll({
      subQuery: false,
      include: [
        {
          model: project_master,
          as: 'project_masters', // this is your alias defined in model
          attributes: ['id','foo','bar'],
          include: [
            {
              model: item_master,
              as: 'item_masters', // this is your alias defined in model
              attributes: ['id','foo','bar']
            }
          ]
        }
      ],
      where: {
         id: workspace_id,
         company_id: company_id
      }
    });
    
    if(!result || !result.length) return res.send('Something went wrong!');
    return res.send(result);
   }

    Now try this, I hope this will solve your issue.

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