Mysql - SQL query to compare the average of two different sql queries with dates

Stefan
July 30, 2023
177 views
0 votes
2 Answers

I have a table with name_id, date and col1-col5 with rates.
I’m looking for a solution to compare the average of the rates of the latest day with the average of the rates of the day before the latest day.
When the average of the latest day is higher then the day before the latest day, then ‘up’. When lower, then ‘down’.

The latest day:

SELECT AVG(CASE
         WHEN COALESCE(`col1`, `col2`, `col3`, `col4`, `col5`) IS NOT NULL THEN 
         (COALESCE(`col1`, 0) + COALESCE(`col2`, 0) + COALESCE(`col3`, 0) + COALESCE(`col4`, 0) + COALESCE(`col5`, 0) ) / 
            (CASE WHEN `col1` IS NULL THEN 0 ELSE 1 END + 
             CASE WHEN `col2` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col3` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col4` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col5` IS NULL THEN 0 ELSE 1 END)
       END) AS Average
       FROM table WHERE `date`= (SELECT MAX(`date`) FROM table) AND name_id=3;

Average: 4.9028

The day before the latest day:

SELECT AVG(CASE
         WHEN COALESCE(`col1`, `col2`, `col3`, `col4`, `col5`) IS NOT NULL THEN 
         (COALESCE(`col1`, 0) + COALESCE(`col2`, 0) + COALESCE(`col3`, 0) + COALESCE(`col4`, 0) + COALESCE(`col5`, 0) ) / 
            (CASE WHEN `col1` IS NULL THEN 0 ELSE 1 END + 
             CASE WHEN `col2` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col3` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col4` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col5` IS NULL THEN 0 ELSE 1 END)
       END) AS Average
       FROM table WHERE `date` = (SELECT MAX(date) FROM table WHERE date < (SELECT MAX(date) FROM table)) AND name_id=3;

Average: 5.3200

This query only compares the rates of the latest day with a ‘fixxed’ rate of 5.00 (not what I need):

SELECT CASE
WHEN AVG(CASE
         WHEN COALESCE(`col1`, `col2`, `col3`, `col4`, `col5`) IS NOT NULL THEN 
         (COALESCE(`col1`, 0) + COALESCE(`col2`, 0) + COALESCE(`col3`, 0) + COALESCE(`col4`, 0)+ COALESCE(`col5`, 0) ) / 
            (CASE WHEN `col1` IS NULL THEN 0 ELSE 1 END + 
             CASE WHEN `col2` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col3` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col4` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col5` IS NULL THEN 0 ELSE 1 END)
       END) < 5.00 THEN 'up' ELSE 'down' END AS 'Rate'
       FROM table WHERE `date`= (SELECT MAX(`date`) FROM table) AND name_id=3;

Rate: up

How to make a query to compare the 2 outputs?

Answers

1 possible way is to calculate the average first, Join and compare the result then –

WITH latest_day_avg AS (
SELECT name_id,
    AVG(CASE
            WHEN COALESCE(`col1`, `col2`, `col3`, `col4`, `col5`) IS NOT NULL 
                THEN (COALESCE(`col1`, 0) + COALESCE(`col2`, 0) + COALESCE(`col3`, 0) + COALESCE(`col4`, 0) + COALESCE(`col5`, 0) ) / 
                     (CASE WHEN `col1` IS NULL THEN 0 ELSE 1 END + 
                      CASE WHEN `col2` IS NULL THEN 0 ELSE 1 END +
                      CASE WHEN `col3` IS NULL THEN 0 ELSE 1 END +
                      CASE WHEN `col4` IS NULL THEN 0 ELSE 1 END +
                      CASE WHEN `col5` IS NULL THEN 0 ELSE 1 END)
                  END) AS Average
FROM 
    table 
WHERE 
    `date` = (SELECT MAX(`date`) FROM table)
GROUP BY name_id
),
prev_day_avg AS(
SELECT name_id,
    AVG(CASE
         WHEN COALESCE(`col1`, `col2`, `col3`, `col4`, `col5`) IS NOT NULL THEN 
         (COALESCE(`col1`, 0) + COALESCE(`col2`, 0) + COALESCE(`col3`, 0) + COALESCE(`col4`, 0) + COALESCE(`col5`, 0) ) / 
            (CASE WHEN `col1` IS NULL THEN 0 ELSE 1 END + 
             CASE WHEN `col2` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col3` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col4` IS NULL THEN 0 ELSE 1 END +
             CASE WHEN `col5` IS NULL THEN 0 ELSE 1 END)
       END) AS Average
FROM 
    table 
WHERE 
    `date` = (SELECT MAX(date) FROM table 
              WHERE date < (SELECT MAX(date) FROM table)) 
GROUP BY name_id
)
SELECT CASE WHEN lda.average < pda.average THEN 'Down'
            WHEN lda.average > pda.average THEN 'Up'
            ELSE 'Equal'
       END
  FROM latest_day_avg lda
  JOIN prev_day_avg pda ON lda.name_id = pda.name_id
 WHERE name_id = 3;

My understanding is that, where there are multiple rows for the same name_id/date pair, the columns col1 – col5 across the multiple rows form a single set. If my understanding is incorrect, you can completely ignore my answer 😉

This is a contrived example to highlight the importance of understanding the difference between the average of all values, and the average of some intermediate averages (where the number of values in the intermediates varies).

Let’s take this modified version of your sample data:

id	name_id	date	col1	col2	col3	col4	col5
1	3	2023-07-28	4.64	4.70	4.80	4.90	5.10
2	3	2023-07-28	4.75	4.86	4.87	5.05	5.15
3	3	2023-07-28	6.30	NULL	NULL	NULL	NULL
4	3	2023-07-29	5.00	5.07	5.15	5.29	5.52
5	3	2023-07-29	5.09	NULL	5.22	5.37	5.52
6	3	2023-07-29	5.30	5.30	5.45	5.50	5.70

And here is the same data with the sum, value count and average per row added:

id	name_id	date	col1	col2	col3	col4	col5	sum	val_count	avg
1	3	2023-07-28	4.64	4.70	4.80	4.90	5.10	24.14	5	4.828000
2	3	2023-07-28	4.75	4.86	4.87	5.05	5.15	24.68	5	4.936000
3	3	2023-07-28	6.30	NULL	NULL	NULL	NULL	6.30	1	6.300000
4	3	2023-07-29	5.00	5.07	5.15	5.29	5.52	26.03	5	5.206000
5	3	2023-07-29	5.09	NULL	5.22	5.37	5.52	21.20	4	5.300000
6	3	2023-07-29	5.30	5.30	5.45	5.50	5.70	27.25	5	5.450000

Now let’s look at the average of the averages vs the average of all values for each name_id/date grouping:

name_id	date	avg_avg	avg
3	2023-07-28	5.3546666667	5.010909
3	2023-07-29	5.3186666667	5.320000

The avg_avg value has decreased between 2023-07-28 and 2023-07-28,
but the avg value has increased for the same period.

Modifying Ankit’s answer to compare the averages, instead of the averages of intermediate averages, we end up with:

WITH latest_day_avg AS (
    SELECT name_id,
        SUM(IFNULL(col1, 0) + IFNULL(col2, 0) + IFNULL(col3, 0) + IFNULL(col4, 0) + IFNULL(col5, 0))
        /
        SUM((`col1` IS NOT NULL) + (`col2` IS NOT NULL) + (`col3` IS NOT NULL) + (`col4` IS NOT NULL) + (`col5` IS NOT NULL)) AS Average
    FROM tbl 
    WHERE `date` = (SELECT MAX(`date`) FROM tbl)
    GROUP BY name_id
),
prev_day_avg AS(
    SELECT name_id,
        SUM(IFNULL(col1, 0) + IFNULL(col2, 0) + IFNULL(col3, 0) + IFNULL(col4, 0) + IFNULL(col5, 0))
        /
        SUM((`col1` IS NOT NULL) + (`col2` IS NOT NULL) + (`col3` IS NOT NULL) + (`col4` IS NOT NULL) + (`col5` IS NOT NULL)) AS Average
    FROM tbl 
    WHERE `date` = (SELECT MAX(date) FROM tbl WHERE date < (SELECT MAX(date) FROM tbl))
    GROUP BY name_id
)
SELECT CASE WHEN lda.average < pda.average THEN 'Down'
            WHEN lda.average > pda.average THEN 'Up'
            ELSE 'Equal'
       END AS Rate
  FROM latest_day_avg lda
  JOIN prev_day_avg pda ON lda.name_id = pda.name_id
 WHERE lda.name_id = 3;

Here’s a db<fiddle.

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Mysql – SQL query to compare the average of two different sql queries with dates

Answers