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Variable loses its value PHP – PHP Versions

I have the code below where my variable $layout loses it’s value and I have no idea why, the layoutContent is just a method that get the template of my website, then
renderOnlyView get the view supposed to render in that template

$layout = $this->layoutContent($layoutParams);
echo ($layout);
$view = $this->renderOnlyView($view, $params);
echo ($layout);

the whole method where the bug occurred

public function renderView(string $view, array $params = [], array $layoutParams = [])
{
    $layout = $this->layoutContent($layoutParams);
    echo ($layout);
    $view = $this->renderOnlyView($view, $params);
    echo ($layout);

    $layout = str_replace('{{ title }}', $layoutParams['title'] ?? 'No title', $layout);
    
    return str_replace('{{ body }}', $view, $layout);
}

and renderOnlyView

protected function renderOnlyView(string $view, array $params): ?string
{
    foreach ($params as $key => $param) {
        $$key = $param;
    }
    ob_start();
    $viewFilePath = Application::$ROOT_DIR . "/views/$view.blade.php";
    if (file_exists($viewFilePath))
        include_once $viewFilePath;
    else
        echo "the view <b>$view</b> is not found";

    return ob_get_clean();
}

layoutContent just in case

public function layoutContent(array $params = [])
{
    $layout = Application::$APP->controller->layout ?? 'main';
    ob_start();
    include_once Application::$ROOT_DIR . "/views/layout/$layout.layout.php";
    $output = ob_get_clean();
    foreach ($params as $key => $param) {
        $output = str_replace('{{ ' . $key . ' }}', $param, $output);
    }

    return $output;
}

more infos: PHP Version: 7.4.3, system ubuntu 20.04

Tags:

2

Answers


  1. Chosen as BEST ANSWER
    0

    Okay guys problem found, i missed a point, this function get called two times, the first time when I'm rendering my view, the second time when my view throw an error and while catching it and trying to display the renderLayout get called again, causing the include_once to return null since it was already included :D


  2. 0

    U missed a point, this function get called two times, the first time when you rendering my view, the second time when you view throw an error and while catching it and trying to display the renderLayout get called again, causing the include_once to return null since it was already included

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