Question 40776 in PHP Question posted in
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Get values from url with PHP

I’m trying to get values from a url using php. With basename I only get the last part but i need the part before that as well.

This is the domain: http://mydomain.nl/first/second/third/

$url = parse_url($entry['source_url']);
$urlFragments = explode('/', $url);
$second = $urlFragments[0];
$third = $urlFragments[1];

I need to use part second and part third.

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3

Answers


  1. 0

    This script can help you
    First of all, to make it simple I remove http:// part and then explode it with / and get a different part of the data which is separated by /

    <?php

$url = "http://mydomain.nl/first/second/third/";
$url = str_replace("http://", "", $url);
$urlFragments = explode('/', $url);

$yourDomain = $urlFragments[0];
$first = $urlFragments[1];
$second = $urlFragments[2];
$third = $urlFragments[3];

echo $first . ", " . $second . ", " . $third;
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  2. 0

    @idka-80 try this,

    $url_components = parse_url($url);
echo "<pre>";
print_r(array_filter(explode("/",$url_components['path'])));
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  3. 0

    As you can tell from the fatal error, you’re making a wrong assumption about how parse_url() works:

    Fatal error: Uncaught TypeError: explode(): Argument #2 ($string) must be of type string, array given

    If you only want a specific fragment, you need to tell which one:

    $url = parse_url($entry['source_url'], PHP_URL_PATH);
// ^ Also give it a better name, such as `$path`

    You also possibly want to discard leading and trailing slashes:

    $urlFragments = explode('/', trim($url, '/'));
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