Question 40190 in PHP Question posted in
Official manual can be found here.

How to use array as … type? – PHP

I want to call a method like that:

public function to(Address|string ...$addresses) {}

I can call it with $obj->to("my-address"). But, when I want to give a list of address, I’m using:

$myList = [ "address-1", "address-2" ];
$obj->to($myList);

But I get this error: must be of type SymfonyComponentMimeAddress|string, array given

Even if it’s with [] :

enter image description here

How can I use array as parameters?

Tags:

2

Answers


  1. 0

    You’re using ... to take every argument. You should spread your array before passing it to to():

    $myList = [ "address-1", "address-2" ];
$obj->to(...$myList);
    Login or Signup to reply.
  2. 0

    You need to add ... in the call to the function as well. That syntax has two complementary meanings, both documented on the same page of the manual.

    • When used in the declaration of the function, as you have, it means "collect separate arguments (which must each be of the correct type, if specified) into an array"
    • When used in calling a function, it means "pass the items of this array as separate arguments"

    So:

    $myList = [ "address-1", "address-2" ];
$obj->to(...$myList);

    Means the same as:

    $obj->to("address-1", "address-2");

    And then the ...$addresses in the function declaration makes that back into an array, checking that each item matches the type declaration Address|string.

    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search