Question 41468 in PHP Question posted in
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I'm trying to swap two number using operator but not able to swap the number please help to solve – PHP

Here, I’m trying to swap the number using PHP but not able to swap.
How to solve that problem.

My Code :

<?php  
$a = 45;  
$b = 78;  
echo "Before swapping:<br><br>";  
echo "a =".$a."  b=".$b;  
echo "<br/><br/>";
// Swapping Logic  
$a=$a+$b;  
$b=$a-$b;  
$a=$a+$b;  
echo "After swapping:<br><br>";  
echo "a =".$a."  b=".$b;  
?>

I’m a beginner in php just learning about logic but getting exception so any body can help how to solve it?

Tags:

4

Answers


  1. 0

    Please replace your code

    // Swapping Logic  

   $a=$a+$b;  
   $b=$a-$b;  
   $a=$a+$b;

    with

        $a=$a+$b;  
    $b=$a-$b;  
    $a=$a-$b;
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  2. 0

    You can also swap the variables this way:

    list($a, $b) = array($b, $a);
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  3. 0

    You can just minus it with the one u added or you can try creating another variable to temporarily store the other value while you swap. storing it on a temporary variable is how people usually do it as if you have done leet code , the bubble sort is a good practice for this kind of logic.

       $a=$a+$b; 
   $b=$a-$b;  
   $a=$a-$b;



// Swapping Logic  
$third = $a;  
$a = $b;  
$b = $third;
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  4. 0

    You can dereference in arrays in one line:

    <?php
$a = 1;
$b = 2;

[$b,$a] = [$a,$b];

echo $a,' ', $b;    // 2 1

    Works as far back as PHP 7.1.0

    Demo: https://3v4l.org/q62Zf#v7.1.0

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