Question 41492 in PHP Question posted in
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PHP cURL POST request (JSON) sending as GET, data not showing in receiving script

I’ve been trying to create a connection between two hosts with a POST request sent as JSON using cURL in PHP. My primary objective is to send data from Host A to Host B (labelled for clarity).

First, looking at network tools in the sender browser, the request type is always GET instead of POST, despite using CURLOPT_POSTFIELDS and CURLOPT_POST. Secondly, the data is not printing/echoing in the receiving browser. However, the hardcoded outputs in the receiving script are printing in both browsers. I’ve tried using CURLOPT_CUSTOMREQUEST ‘POST’ to no avail.

Sender JSON tab: SyntaxError: JSON.parse: unexpected non-whitespace character after JSON data at line 1 column 59 of the JSON data

Sender Raw Data tab: {"ChangeType":"renamed","Path":"C:File1","Param3":"Yes"}receive_jsonpost_test.php is running renamedC:File1YesObject id #1

Code:

<?php

// HOST A (sender)

header("Content-Type:application/json"); 

$testobj = array(
    'ChangeType' => 'renamed',
    'Path' => 'C:\File1',
    'Param3' => 'Yes'
);

$url = '[redacted].edu/receive_jsonpost_test.php';
$ch = curl_init($url);
$payload = json_encode($testobj);
    print($payload);
curl_setopt($ch, CURLOPT_POSTFIELDS, $payload);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
$result = curl_exec($ch);
curl_close($ch);
    print($result);
?>

<?php

// HOST B (recipient)

print('receive_jsonpost_test.php is running ');
$json = file_get_contents('php://input');
$data = json_decode($json);
print($data->ChangeType);
print($data->Path);
print($data->Param3);

print($data);

I know this is probably a pretty basic problem, but I’m fairly new to applied host-to-host communication and any help would be greatly appreciated. Thanks.

Tags:

2

Answers


  1. 0

    If you’re trying to interpret the response from Host A, ie…

    print($result);

    as JSON, you won’t have much luck since Host B does not respond with JSON. Host B’s code should look more like this…

    $json = file_get_contents('php://input');
$data = json_decode($json);

// ...do whatever but no `echo` or `print`

header('content-type: application/json');
echo json_encode($someDataStructure); // now respond with some JSON
exit;

    You should also remove this line from Host A as it too will invalidate a JSON response…

    print($payload);

    looking at network tools in the sender browser…

    Your browser isn’t making the request to Host B, PHP is. If your browser makes a GET request to Host A, then that’s all it will see.

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  2. 0

    If all you want to do is send data to HOST B and have B echo the received data back to HOST A:

    Remove this from HOST A:

    print($payload);

    It will send headers to the Browser. The headers should come from HOST B response headers.

    Same goes for

    header("Content-Type:application/json");

    Again, headers should come come from HOST B response headers.

    HOST A request:

    $postdata= array(
    'ChangeType' => 'renamed',
    'Path' => 'C:\File1',
    'Param3' => 'Yes'
);


curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
$result = curl_exec($ch);
echo $response;

    HOST B possible responses

    header('Content-Type: text/plain');

foreach($_POST as $key => $value){
  echo "$key $valuen"
}

    OR If you want to support both POST and GET

    foreach($_REQUEST as $key => $value){
  echo "$key $valuen"
}

    If you really need JSON:

    $postdata= json_encode(array(
    'ChangeType' => 'renamed',
    'Path' => 'C:\File1',
    'Param3' => 'Yes'
));

curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
curl_setopt($ch, CURLOPT_POST, true);
$result = curl_exec($ch);
echo $response;

    HOST B

    header('content-type: application/json');
echo  file_get_contents('php://input');

    OR

    header('content-type: text/plain');
echo  file_get_contents('php://input');

    OR

    header('content-type: text/plain');
var_export(json_decode(file_get_contents('php://input'),1);

    If you want to do a GET request in a Browser:

    https://example.com?ChangeType=renamed'&Path=C:\File1&Param3=Yes

foreach($_REQUEST as $key => $value){
  echo "$key $valuen"
}
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