Question 137239 in PHP Question posted in
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Php – How to create Carbon object from this string: 2022-06-21T05:52:46.648533678Z?

How to create DateTime object with PHP from this string: 2022-06-21T05:52:46.648533678Z? There is nine numbers after ‘dot’, after seconds.

I tried to use next variants:

<?php
Carbon::createFromFormat('Y-m-dTH:i:s.uP', '2022-06-21T05:52:46.648533678Z');
Carbon::createFromFormat('Y-m-dTH:i:s.vP', '2022-06-21T05:52:46.648533678Z');

And always get an error:

The timezone could not be found in the database
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2

Answers


  1. 0

    The format should be as follows to cope with the 9 numerics after the . PHP only can cope with 6 numerics so the ? are just place holders for anything

    <?php
Carbon::createFromFormat('Y-m-dTH:i:s.u???P', '2022-06-21T05:52:46.648533678Z');
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  2. 0

    'Y-m-dTH:i:s.u???P' format as per RiggsFolly’s solution is the way if you expect only this format.

    If you want to allow more or less digits, note that parse can also do it without having to specify any format:

    echo Carbon::parse('2022-06-21T05:52:46.648533678Z');
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